By the action of a solution of hydrogen chloride in nitromethane, 3-methybut-1 - ene gives a mixture of 2-chloro-3- methylbutane and 2-chloro-2-methylbutane in the ratio (40:60). Under the same conditions, 3,3-dimethybut-1 - ene leads to a mixture of 2-chloro-2,3-dimethylbutane and 2-chloro-3, 3-dimethybultane in the ratio (83:17). Explain these results.
By the action of a solution of hydrogen chloride in nitromethane, 3-methybut-1 - ene gives a mixture of 2-chloro-3- methylbutane and 2-chloro-2-methylbutane in the ratio (40:60). Under the same conditions, 3,3-dimethybut-1 - ene leads to a mixture of 2-chloro-2,3-dimethylbutane and 2-chloro-3, 3-dimethybultane in the ratio (83:17). Explain these results.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![By the action of a solution of hydrogen chloride in nitromethane, 3-methybut-1 - ene gives a mixture of 2-chloro-3-
methylbutane and 2-chloro-2-methylbutane in the ratio (40:60). Under the same conditions, 3,3-dimethybut-1 - ene
leads to a mixture of 2-chloro-2,3-dimethylbutane and 2-chloro-3, 3-dimethybultane in the ratio (83:17). Explain
these results.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2a23509e-9aab-4eec-ad5d-8d10f62d1e15%2F2f54cca1-6971-47f9-a9de-85c27e1ba34c%2F3n76ove_processed.jpeg&w=3840&q=75)
Transcribed Image Text:By the action of a solution of hydrogen chloride in nitromethane, 3-methybut-1 - ene gives a mixture of 2-chloro-3-
methylbutane and 2-chloro-2-methylbutane in the ratio (40:60). Under the same conditions, 3,3-dimethybut-1 - ene
leads to a mixture of 2-chloro-2,3-dimethylbutane and 2-chloro-3, 3-dimethybultane in the ratio (83:17). Explain
these results.
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