BSCS-5B Theory of Automata (Project) Language: {a"b"c* | n€N, m=n+1, k=n-1} Descriptive Definition: Any number of a's followed by (n+1) number of b's and then followed by (n-1) numbers c's. Words (First 10): {2, abb, aabbbc, aaabbbbcc, aaaabbbbbccc, aaaaabbbbbbcccc, aaaaaabbbbbbbccccc, aaaaaaabbbbbbbbcccccc, aaaaaaaabbbbbbbbbccccccc, aaaaaaaaabbbbbbbbbbccccccce...}

BSCS-5B Theory of Automata (Project) Language: {a"b"c* | n€N, m=n+1, k=n-1} Descriptive Definition: Any number of a's followed by (n+1) number of b's and then followed by (n-1) numbers c's. Words (First 10): {2, abb, aabbbc, aaabbbbcc, aaaabbbbbccc, aaaaabbbbbbcccc, aaaaaabbbbbbbccccc, aaaaaaabbbbbbbbcccccc, aaaaaaaabbbbbbbbbccccccc, aaaaaaaaabbbbbbbbbbccccccce...}

Programming Logic & Design Comprehensive

9th Edition

ISBN:9781337669405

Author:FARRELL

Publisher:FARRELL

Chapter8: Advanced Data Handling Concepts

Section: Chapter Questions

Problem 16RQ

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JAVA LANGUAGE CODE Postfix Calculator by CodeChum Admin One good implementation of computing infix expressions is to transform them to postfix and then evaluate via the postfix expression. Infix expressions is the common way of writing arithmetic expressions. The binary operator come between them as shown below: 2 * 5 + 9 - 10 / 20 In postfix expressions, the operands come first before the operator: 2 5 * 9 + 10 20 / - A stack can be used to evaluate postfix expressions. The operands are pushed onto the Stack and when an operator is found two operands are popped and the operation is performed and finally the result is pushed back onto the Stack. The final answer will be the lone element of the Stack. Input The first line contains a positive integer n representing the number of postfix expressions. What follows are n postfix expressions themselves. 5 10 20 + 30 15 2 * + 100 20 30 + / 90 20 10 + + 0 / 9 3 - 10 + 2 * Output A single line containing the result of…
a) L= {anb²n, n>0} b) L= {a²nb, n>0} c) L= {ww], w={a,b}* d) L= {anb²n, n20} U {ww}, w={a,b}* Home work 1- Draw an NPDA for the following languages e) L= {a^b²n, n20} f) L= {a²nb", n>0} g) L= {ww), w={a,b}* h) L= {anb²n, n20} U {ww}, w={a,b}* 2- Write CFG for the following languages a) L= {anb²n, n>0} L= {a²nb", n>0} L= {ww}, w={a,b}* L= {anb²n, n>0} U {ww}, w={a,b}* b) c) d)
Rooks on a rampage def safe_squares_rooks(n, rooks): A generalized n-by-n chessboard has been invaded by a parliament of rooks, each rook represented as a two-tuple (row, column) of the row and the column of the square that the rook is in. Since we are again computer programmers instead of chess players and other normal folks, our rows and columns are numbered from 0 to n - 1. A chess rook covers all squares that are in the same row or in the same column. Given the board size n and the list of rooks on that board, count the number of empty squares that are safe, that is, are not covered by any rook. To achieve this in reasonable time and memory, you should count separately how many rows and columns on the board are safe from any rook. Because permuting the rows and columns does not change the answer to this question, you can imagine all these safe rows and columns to have been permuted to form an empty rectangle at the top left corner of the board. The area of that safe rectangle is…
İN C LANGUAGE Typedef struct Complex { Double a; Double b; } COMP_t, *COMP; write a function which finds and returns the position of the complex number whose absolute value is maximum in a two dimensional array of complex numbers.Absolute value of z=a+bi is |z|=(a^2+b^2)^1/2
C Program / C Language Make a C program for the determinant of multidimensional array. The determinator 6000 just broke. You are task to create another determinator capable of finding the determinant of a 3 x 3 multi dimensional array.
Problem 2: Write a java program that contains: a) The method public static int numberOccurrences(int a, int b) which returns an integer designating the number of appearance of the digit b in the number a. (b must between 0 and 9). b) Write a test program (main) that asks the user to enter an integer number and a digit then invokes (calls) numberOccurrences method. Sample run 1: Enter a number: 11941. Enter a digit: 1 The number of appearance of 1 in 11941 is 3 Sample run 1: Enter a number: 257 Enter a digit: 5
Postfix interpreter def postfix_evaluate(items): When arithmetic expressions are given in the familiar infix notation 2 + 3 * 4, we need to use parentheses to force a different evaluation order than the usual PEMDAS order determined by precedence and associativity. Writing arithmetic expressions in postfix notation (also known as Reverse Polish Notation) may look strange to us humans accustomed to the conventional infix notation, but is computationally far easier to handle, since postfix notation allows any evaluation order to be expressed unambiguously without using any parentheses at all! A postfix expression is given as a list of items that can be either individual integers or one of the strings '+', '-', '*' and '/' for the four possible arithmetic operators. To evaluate a postfix expression using a simple linear loop, use a list as a stack that is initially empty. Loop through the items one by one, in order from left to right. Whenever the current item is an integer, just append…
Postfix interpreter def postfix_evaluate(items): When arithmetic expressions are given in the familiar infix notation 2 + 3 * 4, we need to use parentheses to force a different evaluation order than the usual PEMDAS order determined by precedence and associativity. Writing arithmetic expressions in postfix notation (also known as Reverse Polish Notation) may look strange to us humans accustomed to the conventional infix notation, but is computationally far easier to handle, since postfix notation allows any evaluation order to be expressed unambiguously without using any parentheses at all! A postfix expression is given as a list of items that can be either individual integers or one of the strings '+','- and '/' for the four possible arithmetic operators. To evaluate a postfix expression using a simple linear loop, use a list as a stack that is initially empty. Loop through the items one by one, in order from left to right. Whenever the current item is an integer, just append it to…
String Implement a custom type for representing strings in C++. Allow following operations as well as operators, considering dynamic memory allocation: Operations: • length: determine the length of string upper: convert the string to upper case • lower: convert the string to lower case • at: return character at a given index • substring: extract a substring given start and end • index: find starting index of a substring • compare: compare two strings concat: concatenate/append the argument after current string. Cater cases for different data types such as String, C-string, char, int, float prepend: concatenate/append the argument before current string. Cater cases for different data types such as String, char, int, float Operators: + : for concatenation and prepend operations taking into account different data types and order of argumets = : for assignment • =, !=, : for comparison operations ] : for access to character at a given index >> and << : for output and input a string
Computer Science Data Structures Class: (IN JAVA) Make these matrixes in the same program (A = 3x3, D = 3x3, C = 3x5) These all have to have a sequence and MUST be incorporated in the code (such as C is +2 +2 -2) D = 0,1,2,1,2,3,2,3,4 A = 1,2,3,4,5,6,7,8,9 C = %3D 1,3,5,3,5,7,5,7,9,7,9,11,9,11,13
convert c code to mips these 2 functions are linked with each other. #define MAX_BOARD_SIZE 12 // Players #define PLAYER_EMPTY 0 #define PLAYER_BLACK 1 #define PLAYER_WHITE 2 int board_size; int current_player = PLAYER_BLACK; char board[MAX_BOARD_SIZE][MAX_BOARD_SIZE]; int main(void); void announce_winner(void); unsigned int count_discs(int player); void announce_winner(void) { int black_count = count_discs(PLAYER_BLACK); int white_count = count_discs(PLAYER_WHITE); if (white_count > black_count) { printf("The game is a win for WHITE!\n"); white_count += count_discs(PLAYER_EMPTY); } else if (black_count > white_count) { printf("The game is a win for BLACK!\n"); black_count += count_discs(PLAYER_EMPTY); } else { printf("The game is a tie! Wow!\n"); } printf("Score for black: %d, for white: %d.\n", black_count, white_count); } unsigned int count_discs(int player) { int count = 0; for (int row = 0; row < board_size; ++row) { for (int col = 0; col < board_size; ++col) { if…
#include <bits/stdc++.h>using namespace std;#define numVl 3 struct thNde { thNde* parent; int mat[numVl][numVl]; int x, y; int cost; int level;}; int thPrntMtrx(int mat[numVl][numVl]) { for (int q = 0; q < numVl; q++) { for (int j = 0; j < numVl; j++) printf("%d ", mat[q][j]); printf("\n"); }} thNde* newNode(int mat[numVl][numVl], int x, int y, int newX, int newY, int level, thNde* parent) { thNde* node = new thNde; node->parent = parent; memcpy(node->mat, mat, sizeof node->mat); swap(node->mat[x][y], node->mat[newX][newY]); node->cost = INT_MAX; node->level = level; node->x = newX; node->y = newY; return node;} int row[] = { 1, 0, -1, 0 };int col[] = { 0, -1, 0, 1 }; int calculateCost(int starting[numVl][numVl], int resltng[numVl][numVl]) { int count = 0; for (int q = 0; q < numVl; q++) for (int j = 0; j < numVl; j++) if (starting[q][j] && starting[q][j] != resltng[q][j]) count++; return count;} int isSafe(int x, int y) {…