branch(branch_name, branch.city, assets) customer (customer-name, customer-street, customercity) loan (loan_number, branch_name, amount) borrower (customer_name, loan-number) account (account_number, branchname, balance) depositor (customer_name, account_number) Figure 15.14 Bank database.
branch(branch_name, branch.city, assets) customer (customer-name, customer-street, customercity) loan (loan_number, branch_name, amount) borrower (customer_name, loan-number) account (account_number, branchname, balance) depositor (customer_name, account_number) Figure 15.14 Bank database.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Consider the bank
select T.branch name
from branch T, branch S
where T.assets > S.assets and S.branch city = “Brooklyn”
Write an efficient relational-algebra expression that is equivalent to this query.
Justify your choice
![branch(branch_name, branch.city, assets)
customer (customer-name, customer-street, customercity)
loan (loan_number, branch_name, amount)
borrower (customer_name, loan-number)
account (account_number, branchname, balance)
depositor (customer_name, account_number)
Figure 15.14 Bank database.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6534352c-cb02-435a-bf36-8c66658ec2aa%2F213427d3-65b5-461a-829d-52576899930d%2Fsb9krk.png&w=3840&q=75)
Transcribed Image Text:branch(branch_name, branch.city, assets)
customer (customer-name, customer-street, customercity)
loan (loan_number, branch_name, amount)
borrower (customer_name, loan-number)
account (account_number, branchname, balance)
depositor (customer_name, account_number)
Figure 15.14 Bank database.
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