onvert the following SQL Query  to Relational Algebra : 1. Select customer.phone, customer.address, customer.fullname from customer where exists (select * from billing where billing.cid = customer. Customer_id); 2. Select * from customer where customer.address in (‘Ibri’); 3. Select billing.bill_id from billing Group by bill_id Having count (case when billing.b_status = ‘REJWCTED’ then 1 end) >1;

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