Consider the following SQL query on the university schema: select avg(salary)-(sum(salary) / count(*)) from instructorWe might expect that the result of this query is zero since the average of a set of numbers is defined to be the sum of the numbers divided by the number of numbers. Indeed this is true for the example instructor relation in Figure 2.1. However, there are other possible instances of that relation for which the result would not be zero. Give one such instance, and explain why the result would not be zero. Schema Diagram for University DatabasestudenttakesIDIDcourse_idsec_idsemesterуeargradeпатеdept_nametot_credsectioncoursedepartmentdept namebuildingbudgetadvisorcourse_idsec_idsemesteryearbuildingroom_notime_slot_idcourse_idtitledept_namecreditss idi idtime_slottime slot_iddaystart_timeend_timeprereqinstructorclassroomcourse_idprereq_idIDbuildingroom посараcityпатеdept_namesalaryteachesIDcourse_idsec idsemesterуearDatabase System Concepts - 6th Edition3.3©Silberschatz, Korth and Sudarshan

For numeric values it will always be zero. But when there is a null value the answer will be…

Answered: Consider the following SQL query on the…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Consider the following SQL query on the university schema:
select avg(salary)-(sum(salary) / count(*))
from instructor
We might expect that the result of this query is zero since the average of a set of numbers is defined to be the sum of the numbers divided by the number of numbers. Indeed this is true for the example instructor relation in Figure 2.1. However, there are other possible instances of that relation for which the result would not be zero. Give one such instance, and explain why the result would not be zero.