The table STUDENT has the attributes STUDENT_ID, NAME, SCHOOL_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes? a. SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL b. SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) c. SELECT * SCHOOL_ID FROM STUDENT NATURAL JOIN SCHOOL d. SELECT * SCHOOL_ID FROM STUDENT, SCHOOL WHERE SCHOOL_ID = SCHOOL_ID
The table STUDENT has the attributes STUDENT_ID, NAME, SCHOOL_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes? a. SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL b. SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) c. SELECT * SCHOOL_ID FROM STUDENT NATURAL JOIN SCHOOL d. SELECT * SCHOOL_ID FROM STUDENT, SCHOOL WHERE SCHOOL_ID = SCHOOL_ID
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Question
The table STUDENT has the attributes STUDENT_ID, NAME, SCHOOL_ID, and ADDR. The table SCHOOL has the attributes SCHOOL_ID, NAME, and STATE_CODE. Assume that there is a 1:N relation between SCHOOL and STUDENT. Which of the following creates a table that shows the STUDENT attributes and the corresponding SCHOOL attributes?
| a. |
SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL |
|
| b. |
SELECT * SCHOOL_ID FROM STUDENT JOIN SCHOOL USING(SCHOOL_ID) |
|
| c. |
SELECT * SCHOOL_ID FROM STUDENT NATURAL JOIN SCHOOL |
|
| d. |
SELECT * SCHOOL_ID FROM STUDENT, SCHOOL WHERE SCHOOL_ID = SCHOOL_ID |
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