Br Br NaOH DMF NaOCH₂CH3 HOCH₂CH3

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Do both of these mechanisms yield two products?

For the first one, would both SN2 and E2 be yielded? Which one would be major though?

And for the second one, would both SN1 and E1 be yielded?

### Chemical Reactions and Mechanisms

#### Reaction 1:

- **Starting Material:** Cyclopentyl bromide
- **Reagent:** Sodium hydroxide (NaOH)
- **Solvent:** Dimethylformamide (DMF)

**Description:**
This diagram represents a substitution reaction where cyclopentyl bromide reacts with sodium hydroxide in the presence of DMF. The bromine (Br) on cyclopentyl bromide is expected to be replaced by the hydroxide group (OH) from NaOH, forming cyclopentanol.

#### Reaction 2:

- **Starting Material:** (R)-2-bromobutane
- **Reagent:** Sodium ethoxide (NaOCH₂CH₃)
- **Solvent:** Ethanol (HOCH₂CH₃)

**Description:**
This diagram illustrates an elimination reaction where (R)-2-bromobutane reacts with sodium ethoxide in ethanol. The process favors the formation of an alkene by removing HBr from the starting material, likely forming butene isomers depending on reaction conditions.

These reactions are typical for understanding nucleophilic substitution and elimination in organic chemistry.
Transcribed Image Text:### Chemical Reactions and Mechanisms #### Reaction 1: - **Starting Material:** Cyclopentyl bromide - **Reagent:** Sodium hydroxide (NaOH) - **Solvent:** Dimethylformamide (DMF) **Description:** This diagram represents a substitution reaction where cyclopentyl bromide reacts with sodium hydroxide in the presence of DMF. The bromine (Br) on cyclopentyl bromide is expected to be replaced by the hydroxide group (OH) from NaOH, forming cyclopentanol. #### Reaction 2: - **Starting Material:** (R)-2-bromobutane - **Reagent:** Sodium ethoxide (NaOCH₂CH₃) - **Solvent:** Ethanol (HOCH₂CH₃) **Description:** This diagram illustrates an elimination reaction where (R)-2-bromobutane reacts with sodium ethoxide in ethanol. The process favors the formation of an alkene by removing HBr from the starting material, likely forming butene isomers depending on reaction conditions. These reactions are typical for understanding nucleophilic substitution and elimination in organic chemistry.
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