boiling point boiling point BPtof pure A vapour composition liquid composition Bpt of pure B OA 1.0B 1.0 A OB mole fractions Create your scale on the x and y axes. Estimate the boiling point of the mixture which is composed of 80% A and 20% B. What will be the vapor composition? SUBMIT YOUR SOLUTION WITH ILLUSTRATION AND APPROPRIATE LABELS ON THE DIAGRAM.

boiling point boiling point BPtof pure A vapour composition liquid composition Bpt of pure B OA 1.0B 1.0 A OB mole fractions Create your scale on the x and y axes. Estimate the boiling point of the mixture which is composed of 80% A and 20% B. What will be the vapor composition? SUBMIT YOUR SOLUTION WITH ILLUSTRATION AND APPROPRIATE LABELS ON THE DIAGRAM.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Boiling Point Elevation/Freezing Point Depression T = m K where, for freezing point depression: T = T(pure solvent) - T(solution) and for boiling point elevation: T = T(solution) - T(pure solvent) m = (# moles solute / Kg solvent) Kb = boiling point elevation constant. Kf = freezing point depression constant. Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow. Solvent Formula Kb(°C / m) Kf(°C / m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02
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2. A benzene (B)-toluene (T) solution is in equilibrium with its vapor at 80°C. If уB -0.670, calculate XB and the total vapor pressure of the solution. The vapor pressures at 80°C of benzene and toluene are 100.4 kPa and 38.7 kPa, respectively. (answer: XB-0.439, P= 65.8 kPa)** Calculate the equilibrium concentration (represented as a mole fraction) of carbon dioxide in fat given that
The experimental data in the table was collected during a freezing point depression study where BHT (butylated hydroxytoluene) was the solvent. Mass Mass of BHT of unknown 8.526 g 1.316 g Use this data to calculate the molar mass of the unknown solute. molar mass= 16962 Incorrect psy HW 3.pdf Freezing point of pure BHT 74.60 °C APA Title Page -....doc Freezing point of BHT and unknown solution 71.69 °C PSY Final Project....pdf A K₁ for BHT 6.83 °C/m g/mol SH
There are two separate phases, one with a composition of 12% phenol and the other with a composition of 60% phenol, from a 210 gram phenol-water mixture with 35% phenol at 60oC. Calculate the masses of these phases.
3. Refer to the phase diagram depicted below: When 7 moles of A and 3 moles of B are mixed at 50oC which is then cooled to 10oC the sample turns into two liquid phases, phase I has mole fraction xB=0.14 (see diagram below). Find the phase II mole fraction xB, and then calculate the ratio of amount of substance in phase I to that in phase II using Lever rule. Please enter your answer as a number with two decimals. for example, if the ratio you calculated is 2:3, you enter as 0.67
Which of the following mixtures contains 2 phases and 3 components? Choose all that apply.I. Water at its freezing pointII. A mixture of water, ethanol, and CO2 under vapor-liquid equilibriumIII. An aqueous solution of NaClIV. A saturated aqueous solution in equilibrium with undissolved solid MgCl2 and CuSO4
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A simple distillation flask (V=2L) is initially charged with 320 moles of a solution consisting of 40 mole ethanol (A) and 60 mole % water (B). This solution is evaporated at a constant rate of 1.6 moles/min. The vapor is then condensed and collected in separate flask as distillate. Determine mole fraction of ethanol in the distillate when three-fifth (3/5) of the solution is evaporated and condensed. The equilibrium relation between XA (mol fraction of A in liquid phase) and ya (mol fraction. of A in vapor phase) is: Y/XA=2 Lütfen birini seçin: a.0.620 b.0.580 c.0.660 d.0.690 e.0.560
1. Part A Solution temperature = 24 °C Conductivity of instrument grade water = 1.043 uScm! Conductivity of deionised water = 1.74 µScm! Conductivity of tap water = 330 μScml On the basis of data above comment on conditions of the different water grades. 2. The experimental data for electrolytes in Part B are given below: Electrolyte c (M) K (ms.cm') HC1 0.01 5.06 KCI 0.01 1.415 NaCl 0.01 1.236 CaCl2 0.01 2.30 КОН 0.01 2.29 CH3OH 0.01 0.003 K2SO4 0.01 2.65 Calculate molar conductivity A of each electrolyte solution in Sm/mol above. Correct for the conductivity of deionized water.
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