Block 1, of mass m1 = 2.30 kg , moves along a frictionless air track with speed v1 = 25.0 m/s . It collides with block 2, of mass m2 = 31.0 kg . which was initially at rest. The blocks stick together after the collision. (Figure 1) Find the magnitude Pi of the total initial momentum of the two-block system. Express your answer numerically. > View Available Hint(s) nν ΑΣφ Pi = 46.5 kg - m/s Submit Previous Answers Figure < 1 of 1 > X Incorrect; Try Again; 9 attempts remaining Before collision: m2 Part B Find vf. the magnitude of the final velocity of the two-block system. Express your answer numerically. > View Available Hint(s) After collision: Hνα ΑΣΦ Uf = Im/s Cor Block 1, of mass m1 = 2.30 kg, moves along a frictionless air track with speed vi = 25.0 m/s. It collides with block 2, of mass m2 = 31.0 kg, which was initially at rest. The blocks stick together after the collision. (Figure 1) Submit Part C Figure < 1 of 1 What is the change AK = Kinal - Kinitial in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules. Before collision: • View Available Hint(s) т, т 2 ανα ΑΣφ- ДК - After collision: Submit Provide Feedback

College Physics
11th Edition
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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Block 1, of mass m1 = 2.30 kg , moves along a frictionless air track with speed
v1 = 25.0 m/s . It collides with block 2, of mass m2 = 31.0 kg . which was
initially at rest. The blocks stick together after the collision. (Figure 1)
Find the magnitude Pi of the total initial momentum of the two-block system.
Express your answer numerically.
> View Available Hint(s)
nν ΑΣφ
Pi = 46.5
kg - m/s
Submit
Previous Answers
Figure
< 1 of 1 >
X Incorrect; Try Again; 9 attempts remaining
Before collision:
m2
Part B
Find vf. the magnitude of the final velocity of the two-block system.
Express your answer numerically.
> View Available Hint(s)
After collision:
Hνα ΑΣΦ
Uf =
Im/s
Transcribed Image Text:Block 1, of mass m1 = 2.30 kg , moves along a frictionless air track with speed v1 = 25.0 m/s . It collides with block 2, of mass m2 = 31.0 kg . which was initially at rest. The blocks stick together after the collision. (Figure 1) Find the magnitude Pi of the total initial momentum of the two-block system. Express your answer numerically. > View Available Hint(s) nν ΑΣφ Pi = 46.5 kg - m/s Submit Previous Answers Figure < 1 of 1 > X Incorrect; Try Again; 9 attempts remaining Before collision: m2 Part B Find vf. the magnitude of the final velocity of the two-block system. Express your answer numerically. > View Available Hint(s) After collision: Hνα ΑΣΦ Uf = Im/s
Cor
Block 1, of mass m1 = 2.30 kg, moves along a
frictionless air track with speed vi = 25.0 m/s. It
collides with block 2, of mass m2 = 31.0 kg, which
was initially at rest. The blocks stick together after the
collision. (Figure 1)
Submit
Part C
Figure
< 1 of 1
What is the change AK = Kinal - Kinitial in the two-block system's kinetic energy due to the collision?
Express your answer numerically in joules.
Before collision:
• View Available Hint(s)
т,
т
2
ανα ΑΣφ-
ДК -
After collision:
Submit
Provide Feedback
Transcribed Image Text:Cor Block 1, of mass m1 = 2.30 kg, moves along a frictionless air track with speed vi = 25.0 m/s. It collides with block 2, of mass m2 = 31.0 kg, which was initially at rest. The blocks stick together after the collision. (Figure 1) Submit Part C Figure < 1 of 1 What is the change AK = Kinal - Kinitial in the two-block system's kinetic energy due to the collision? Express your answer numerically in joules. Before collision: • View Available Hint(s) т, т 2 ανα ΑΣφ- ДК - After collision: Submit Provide Feedback
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