Biologists were studying the proportions of cats that had spotted markings on their fur in two populations of cats, C and F. An independent random sample of cats was taken from each population, and the difference between the sample proportions of cats with the spotted markings (C minus F) was 0.62. Under the assumption that all conditions for inference were met, a hypothesis test was conducted with the alternative hypothesis being that the population proportions are not equal. The p-value of the test was 0.01. Which of the following is the correct interpretation of the p-value? If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 or at most −0.62is 0.01. Answer A: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 or at most negative 0.62 is 0.01. A If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01. Answer B: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01. B If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at most −0.62 is 0.01. Answer C: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at most negative 0.62 is 0.01. C If the difference in proportions of cats with spotted markings between the two populations is actually 0.62, the probability of observing that difference is 0.01. Answer D: If the difference in proportions of cats with spotted markings between the two populations is actually 0.62, the probability of observing that difference is 0.01. D If the difference in proportions of cats with spotted markings between the two populations is actually 0.01, the probability of observing that difference is 0.62.

Biologists were studying the proportions of cats that had spotted markings on their fur in two populations of cats, C and F. An independent random sample of cats was taken from each population, and the difference between the sample proportions of cats with the spotted markings (C minus F) was 0.62. Under the assumption that all conditions for inference were met, a hypothesis test was conducted with the alternative hypothesis being that the population proportions are not equal. The p-value of the test was 0.01. Which of the following is the correct interpretation of the p-value? If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 or at most −0.62is 0.01. Answer A: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 or at most negative 0.62 is 0.01. A If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01. Answer B: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01. B If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at most −0.62 is 0.01. Answer C: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at most negative 0.62 is 0.01. C If the difference in proportions of cats with spotted markings between the two populations is actually 0.62, the probability of observing that difference is 0.01. Answer D: If the difference in proportions of cats with spotted markings between the two populations is actually 0.62, the probability of observing that difference is 0.01. D If the difference in proportions of cats with spotted markings between the two populations is actually 0.01, the probability of observing that difference is 0.62.

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Description: Biologists were studying the proportions of cats that had spotted markings on their fur in two populations of cats, C and F. An independent random sample of cats was taken from each population, and the difference between the sample proportions of cat

MATLAB: An Introduction with Applications

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Which of the following is the correct interpretation of the p-value?

If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 or at most −0.62is 0.01.

Answer A: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 or at most negative 0.62 is 0.01.

A
If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01.

Answer B: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01.

B
If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at most −0.62 is 0.01.

Answer C: If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at most negative 0.62 is 0.01.

C
If the difference in proportions of cats with spotted markings between the two populations is actually 0.62, the probability of observing that difference is 0.01.

Answer D: If the difference in proportions of cats with spotted markings between the two populations is actually 0.62, the probability of observing that difference is 0.01.

D
If the difference in proportions of cats with spotted markings between the two populations is actually 0.01, the probability of observing that difference is 0.62.

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