Below is the equation for the alpha decay of Rn-222: 22286Rn --> 42He + XWhat is the correct identity of X? Group of answer choicesRadium-86Radium-218Polonium-220Polonium- 218

Alpha particle contains 2 protons and 2 neutrons and thus have a mass number of 4. During alpha decay it emits alpha particles which are equivalent to helium nuclei. It changes atomic number by 2 and mass number by 4.86222Rn→24He+84218Po The correct answer in the choice is Polonium-218. Sum of superscripts and subscripts are same on each side of the equation.

Answered: Below is the equation for the alpha…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Below is the equation for the alpha decay of Rn-222:

²²²₈₆Rn --> ⁴₂He + X

What is the correct identity of X?

Group of answer choices

Radium-86

Radium-218

Polonium-220

Polonium- 218

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