A rock contains 0.697 mg of 206pb for every 1.000 mg of 238 U present. Assuming that no lead was originally present, that all the 206pb formed over the years has remained in the rock, and that thet1/2number of nuclides in intermediate stages of decay between 238U and 206pb is negligible, calculate the age of the rock. (For 238U,4.5x10⁹years.)yr=

Given, Mass of 206Pb = 0.697 mg Mass of 238U = [A]0 = 1.000 mg Half life period for 238U = t1/2 =…

A rock contains 0.697 mg of 206pb for every 1.000 mg of 238 U present. Assuming that no lead was originally present, that all the 206pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238 U and 206pb is negligible, calculate the age of the rock. (For 238 U, t₁/2 = 4.5x 109 years.) yr

A rock contains 0.697 mg of 206pb for every 1.000 mg of 238 U present. Assuming that no lead was originally present, that all the 206pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238 U and 206pb is negligible, calculate the age of the rock. (For 238 U, t₁/2 = 4.5x 109 years.) yr

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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