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A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)

A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter21: Nuclear Chemistry
Section: Chapter Questions
Problem 21.43QE
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A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)
Transcribed Image Text:A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)
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