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A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)

A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)
Transcribed Image Text:A rock contains 0.617 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the 206Pb formed over the years has remained in the rock, and that the number of nuclides in intermediate stages of decay between 238U and 206 Pb is negligible, calculate the age of the rock. (For 238U, t1/2 = 4.5 X 109 years.)
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