The question is in the image. Write a balanced nuclear reaction for the following:\[\begin{aligned}&{}^{216}_{84}\text{Po} \rightarrow {}^0_{-1}\beta + \text{_____} \\\end{aligned}\]When balancing the nuclear reaction, explain the following:- How does the Law of Conservation of Matter dictate what the daughter nuclide is?- How do we calculate the atomic mass and atomic number for the daughter nuclide?- Where do we look up what the new daughter nuclide element is?

The balanced equation is, P84216o →β-10 + A85216t According to the law of conservation of mass,…

Answered: Write a balanced nuclear reaction for…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

100%

The question is in the image.

Write a balanced nuclear reaction for the following:

\[
\begin{aligned}
&{}^{216}_{84}\text{Po} \rightarrow {}^0_{-1}\beta + \text{_____} \\
\end{aligned}
\]

When balancing the nuclear reaction, explain the following:

- How does the Law of Conservation of Matter dictate what the daughter nuclide is?
- How do we calculate the atomic mass and atomic number for the daughter nuclide?
- Where do we look up what the new daughter nuclide element is?

Expert Solution

Step 1

The balanced equation is,

${}_{84}^{216}P o \to {}_{- 1}^{0}β + {}_{85}^{216}A t$

According to the law of conservation of mass, total mass is always conserved. It means that mass of reactants is equals to the mass of the products formed.

Hence, if we know the mass of reactant, mass of the product can be obtained.

Sum of mass number on reactants side = Sum of mass number on product side

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions