Here are summary statistics for randomly selected weights of newborn girls: - Sample size (\( n \)): 36- Sample mean (\( \bar{x} \)): 3180.6 g- Sample standard deviation (\( s \)): 700.5 gUse a confidence level of 95% to complete parts (a) through (d) below.**b. Find the margin of error:**\( E = 237 \, \text{g} \)(Round to one decimal place as needed.)**c. Find the confidence interval estimate of \( \mu \):**\[ \_\_\_ < \mu < \_\_\_ \] g(Round to one decimal place as needed.)**Additional Options:**- Help me solve this- View an example- Get more help**Navigation:**- Previous- Next**Note:** There are no graphs or diagrams in the image.

Answered: Image /qna-images/answer/cf350faf-bad3-4796-92c5-1e1628d0e456.jpg

Answered: below D. FU Ue margin ui erru. E= 237 g…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please show how to get the answer but also show how to put into the graphing calculator.
Please no written by hand solution 1) Suppose you want to know the percentage of university students who consider themselves beer drinkers. You perform a pre-test and find that, in a small sample that is not representative of the target market, 47% of students say they drink beer. If you want 95% confidence that you have the correct answer (within +/- 3%) when you calculate the mean in your survey, what size representative sample must you obtain? 2) Now, suppose you want to know the average amount of beer consumed in a typical week by a beer-drinking student, within 3 beers per week. Calculate the required sample size. (Hint: You will need to estimate the standard error using one of the techniques described in the lecture and in the textbook.) 3) Describe the method you used to estimate the standard error, in detail.
Can anyone get this right. I've tried multiple answers, but none of them are correct. One picture has the info needed and thr other one contains the actual question for the confidence level. The answer is NOT WHAT'S PICTURED OR 2.547, 6.547
Q7. The 95% C.I. is calculated as 95% C.I.= X ± 1.96 and the п 99% C.I. is calculated as 99% C.I.= X ± 2.57 How will happen the Confidence Interval change when it is increased from 95% to 99% using the same sample. A. Widens with the same centre. B. Narrows with different centres. C. Same range with different centres. D. Widens with different centres. О А. А ОВ. В С. С O D. D
Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to keep in stock. At the end of one year, the store used the weekly sales information to construct a 95% confidence interval for the mean number of emeralds sold per week. The confidence interval they calculated was (3.25,4.51). Use the confidence interval to find the point estimate for the mean and the margin of error. Give your answers precise to two decimal places.
If n 180 and p (p-hat) =0.07, find the margin of error at a 95% confidence level. Round to 4 places. Z-scores may be rounded to 3 places or exact using technology.
Other things being equal, the margin of error of a confidence interval increases as the a. sample size increases. b. sample mean increases. confidence level increases. C. d. confidence level decreases. none of the above. е. An SRS of 100 postal employees found that the average time these employees had worked for the postal service was x 7 years with standard deviation s 2 years. Assume the distributi on of the time the population of employees have worked for the postal service is approximately Normal. Which of the following gives the correct 95% confidence interval for the mean time u the population of postal service employees have worked for the postal service? 7 2 %3D a. b. 7 1.984 7 0.525 C. d. 7 0.4 7 0.2 e.

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