I am confused about how to find the confidence interval (at the 90% level) of the remaining data points on part C. Which then leads to not being able to figure out part D to find that higher level of confidence.
I am confused about how to find the confidence interval (at the 90% level) of the remaining data points on part C. Which then leads to not being able to figure out part D to find that higher level of confidence.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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I am confused about how to find the confidence interval (at the 90% level) of the remaining data points on part C. Which then leads to not being able to figure out part D to find that higher level of confidence.
I attached the chart of confidence levels for these questions. Thank you!

Transcribed Image Text:Show all work and calculations:
1. The following data were obtained in the determination of the density of water:
Density (g/mL): 0.986, 0.984, 0,954, 0.990, 0.980
a.
Determine the mean and standard deviation for this data set.
Ncan: 0.979
Stenderd Devietion- 0.0128
b. Perform a Grubbs' outlier test. Can a data point be discarded at the 90% confidence level?
We con
discord the 0.954.
c. Determine the mean, standard deviation, and confidence interval (at the 90% level) of the
remaining data points.
Mean= 0.985
starderd Daviction= 0.003
d. In the Grubbs' test, is there a higher level of confidence that would require you to keep the
outlier (0.954) in the data set? If so, what level is that? Explain why using a higher level of
confidence makes it more difficult to discard an outlier.

Transcribed Image Text:PENDIX 2: Critical Grubbs Value (gcrit) Table
95% confidence
99% confidence
Number of
90% confidence
Observations (n)
1.155
1.153
1.463
1.148
1.492
4
1.425
1.602
1.672
1.749
1.729
1.822
1.944
6.
1.828
1.938
2.097
7.
1.909
2.032
2.221
1.977
2.110
2.323
9.
10
2.036
2.176
2.410
Expert Solution

Step 1
I am only solving C & D that based on your calculations.
c) We see that, removing the outlier value, there are 4 data points.
Hence, sample size = n = 4.
Mean = m = 0.983
S.D. = s = 0.003
We see that, for sample size (no. of observations) 4, the 90% confidence level is 1.425.
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