A research intern would like to estimate, with 95% confidence, the true proportion of employees who are unsatisfied with their current job. No preliminary estimate is available. The researcher wants the estimate to be within 5% of the population mean. The research intern has a table to use: z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 They complete the calculation for the minimum sample size as follows.... n=1.962(0.5)(0.5)52≈0.038 Which the intern then rounds up to 1. Which value in the calculation is incorrect?
A research intern would like to estimate, with 95% confidence, the true proportion of employees who are unsatisfied with their current job. No preliminary estimate is available. The researcher wants the estimate to be within 5% of the population mean. The research intern has a table to use: z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 They complete the calculation for the minimum sample size as follows.... n=1.962(0.5)(0.5)52≈0.038 Which the intern then rounds up to 1. Which value in the calculation is incorrect?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A research intern would like to estimate, with 95% confidence, the true proportion of employees who are unsatisfied with their current job. No preliminary estimate is available. The researcher wants the estimate to be within 5% of the population mean.
The research intern has a table to use:
z0.10 | z0.05 | z0.025 | z0.01 | z0.005 |
1.282 | 1.645 | 1.960 | 2.326 | 2.576 |
They complete the calculation for the minimum
n=1.962(0.5)(0.5)52≈0.038
Which the intern then rounds up to 1. Which value in the calculation is incorrect?
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this solution is incorrect since the
confidence level is 90%
margin of error is 3%
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