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Below are the reduction half reactions for chemolithoautotrophic denitrification, where hydrogen is a source of electrons and energy and nitrate is the terminal electron acceptor. +10e-> N₂ (E° = +0.74 V) • NO3 + • H*+2e -> H₂ (E° = -0.42 V) If you balance and combine the reactions so that 420 moles of H₂ gas are oxidized to H*, how many moles of N₂ gas will be produced?

Below are the reduction half reactions for chemolithoautotrophic denitrification, where hydrogen is a source of electrons and energy and nitrate is the terminal electron acceptor. +10e-> N₂ (E° = +0.74 V) • NO3 + • H*+2e -> H₂ (E° = -0.42 V) If you balance and combine the reactions so that 420 moles of H₂ gas are oxidized to H*, how many moles of N₂ gas will be produced?

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
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Problem 19.150QP
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Below are the reduction half reactions for chemolithoautotrophic denitrification, where hydrogen is a source of electrons and energy and nitrate is the terminal electron acceptor. • NO3 + 10e -> N₂ (E° = +0.74 V) • H* + 2e -> H₂ (E° = -0.42 V) If you balance and combine the reactions so that 420. moles of H₂ gas are oxidized to H*, how many moles of N₂ gas will be produced?
Transcribed Image Text:Below are the reduction half reactions for chemolithoautotrophic denitrification, where hydrogen is a source of electrons and energy and nitrate is the terminal electron acceptor. • NO3 + 10e -> N₂ (E° = +0.74 V) • H* + 2e -> H₂ (E° = -0.42 V) If you balance and combine the reactions so that 420. moles of H₂ gas are oxidized to H*, how many moles of N₂ gas will be produced?
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