Below are some standard electrode potentials Ca" (aq) / Cd(s) Cu"(aq) / Cu(s) 1:(aq), 21'(aq/Pt E"/Volts - 0.40 + 0.34 + 0.54 It would be expected that * The calculated emf of the cell Cu(s) / Cu²"(aq) "»(s), 2F(aq/Pt would be + 0.88V. B Potassium iodide solution would reduce cadmium sulphate to cadmium Cadmium inetal would liberate copper from aqueous copper sulphate D The calculated emf of the cell Cu(s) /Cu"(aq) Ca"(aq) / Cd(s) would be + 0.74V

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Chapter1: Chemical Foundations
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Below are some suandard electrode potentials
E/Volts
16.
Cd (aq) / Cd(s)
Cu"(aq) / Cu(s)
1:(aq), 21'(aqVPt
- 0.40
+ 0.34
+ 0.54
It would be expected that
* The calculatcd emf of the cell Cu(s)/ Cu"(aq) (s), 2r{aqYPt would be + 0.88V.
B Potassium iodide solution would reduce cadmium sulphate to cadmium
C Cadmium inetal would liberate copper from aqueous copper sulphate
D The calculated emf of the cell Cu(s) / Cu"(aq)Ca*(aq)/ Ca(s) would be + 0.74V
Transcribed Image Text:Below are some suandard electrode potentials E/Volts 16. Cd (aq) / Cd(s) Cu"(aq) / Cu(s) 1:(aq), 21'(aqVPt - 0.40 + 0.34 + 0.54 It would be expected that * The calculatcd emf of the cell Cu(s)/ Cu"(aq) (s), 2r{aqYPt would be + 0.88V. B Potassium iodide solution would reduce cadmium sulphate to cadmium C Cadmium inetal would liberate copper from aqueous copper sulphate D The calculated emf of the cell Cu(s) / Cu"(aq)Ca*(aq)/ Ca(s) would be + 0.74V
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