Be sure to answer all parts. Using the data in the table, calculate Kp and AG for this reaction at 25°C. PCI5(g) = PC138) + Cl2(g) AG° Initial Partial Substance f Pressure (atm) (kJ/mol) C2(8) 0.358 PC13(g) -286 0.213 PCI5(g) -325 0.00320 Kp= X 10 AG= kJ/mol
Be sure to answer all parts. Using the data in the table, calculate Kp and AG for this reaction at 25°C. PCI5(g) = PC138) + Cl2(g) AG° Initial Partial Substance f Pressure (atm) (kJ/mol) C2(8) 0.358 PC13(g) -286 0.213 PCI5(g) -325 0.00320 Kp= X 10 AG= kJ/mol
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Calculating \( K_P \) and \(\Delta G\) for a Chemical Reaction at 25°C**
**Reaction:**
\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]
**Table: Thermodynamic Data and Initial Partial Pressures**
| **Substance** | \( \Delta G_f^\circ \) (kJ/mol) | **Initial Partial Pressure (atm)** |
|---------------|-------------------|-------------------------|
| Cl\(_2\)(g) | 0 | 0.358 |
| PCl\(_3\)(g) | -286 | 0.213 |
| PCl\(_5\)(g) | -325 | 0.00320 |
**Calculations:**
1. **Equilibrium Constant \( K_P \):**
To determine \( K_P \), use the equation:
\[
K_P = \left( \frac{\text{Partial Pressure of Products}}{\text{Partial Pressure of Reactants}} \right) = \frac{(P_{\text{PCl}_3})(P_{\text{Cl}_2})}{P_{\text{PCl}_5}}
\]
2. **Change in Gibbs Free Energy \(\Delta G\):**
\(\Delta G\) can be calculated using:
\[
\Delta G = \Delta G_f^\circ \text{ (Products)} - \Delta G_f^\circ \text{ (Reactants)}
\]
**Note:**
- Be sure to compute the values using the data from the table provided above.
- Ensure accuracy by checking units and making sure all values are used appropriately.
\[ K_P = \, \, \times 10 \]
\[ \Delta G = \, \, \text{kJ/mol} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F264afef6-5fb8-47a1-a0f2-19efba1e1114%2Fdc739d2c-2add-42c2-a33c-52440553d0e9%2F725o61p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Calculating \( K_P \) and \(\Delta G\) for a Chemical Reaction at 25°C**
**Reaction:**
\[ \text{PCl}_5(g) \rightleftharpoons \text{PCl}_3(g) + \text{Cl}_2(g) \]
**Table: Thermodynamic Data and Initial Partial Pressures**
| **Substance** | \( \Delta G_f^\circ \) (kJ/mol) | **Initial Partial Pressure (atm)** |
|---------------|-------------------|-------------------------|
| Cl\(_2\)(g) | 0 | 0.358 |
| PCl\(_3\)(g) | -286 | 0.213 |
| PCl\(_5\)(g) | -325 | 0.00320 |
**Calculations:**
1. **Equilibrium Constant \( K_P \):**
To determine \( K_P \), use the equation:
\[
K_P = \left( \frac{\text{Partial Pressure of Products}}{\text{Partial Pressure of Reactants}} \right) = \frac{(P_{\text{PCl}_3})(P_{\text{Cl}_2})}{P_{\text{PCl}_5}}
\]
2. **Change in Gibbs Free Energy \(\Delta G\):**
\(\Delta G\) can be calculated using:
\[
\Delta G = \Delta G_f^\circ \text{ (Products)} - \Delta G_f^\circ \text{ (Reactants)}
\]
**Note:**
- Be sure to compute the values using the data from the table provided above.
- Ensure accuracy by checking units and making sure all values are used appropriately.
\[ K_P = \, \, \times 10 \]
\[ \Delta G = \, \, \text{kJ/mol} \]
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