Be sure to answer all parts. Fluoridation is the process of adding fluorine compounds to drinking water to help fight tooth decay. A concentration of 1 ppm of fluorine is sufficient for the purpose (1 ppm means one part per million, or 1 g of fluorine per 1 million g of water). The compound normally chosen for fluoridation is sodium fluoride, which is also added to some toothpastes. Calculate the quantity of sodium fluoride in kilograms needed per year for a city of 50,000 people if the daily consumption of water per person is 105.0 gallons. (Sodium fluoride is 45.0 percent fluorine by mass. 1gallon =3.785 L; 1 ton = 2000 lb; 1 lb = 453.6 g; density of water = 1.0 g/mL) Enter your answer in scientific notation.
Be sure to answer all parts. Fluoridation is the process of adding fluorine compounds to drinking water to help fight tooth decay. A concentration of 1 ppm of fluorine is sufficient for the purpose (1 ppm means one part per million, or 1 g of fluorine per 1 million g of water). The compound normally chosen for fluoridation is sodium fluoride, which is also added to some toothpastes. Calculate the quantity of sodium fluoride in kilograms needed per year for a city of 50,000 people if the daily consumption of water per person is 105.0 gallons. (Sodium fluoride is 45.0 percent fluorine by mass. 1gallon =3.785 L; 1 ton = 2000 lb; 1 lb = 453.6 g; density of water = 1.0 g/mL) Enter your answer in scientific notation.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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| Be sure to answer all parts. Fluoridation is the process of adding fluorine compounds to drinking water to help fight tooth decay. A concentration of 1 ppm of fluorine is sufficient for the purpose (1 ppm means one part per million, or 1 g of fluorine per 1 million g of water). The compound normally chosen for fluoridation is sodium fluoride, which is also added to some toothpastes. Calculate the quantity of sodium fluoride in kilograms needed per year for a city of 50,000 people if the daily consumption of water per person is 105.0 gallons. (Sodium fluoride is 45.0 percent fluorine by mass. 1gallon =3.785 L; 1 ton = 2000 lb; 1 lb = 453.6 g; density of water = 1.0 g/mL) Enter your answer in scientific notation. |
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