Be sure to answer all parts. Draw a stepwise mechanism for the following reaction: Part 1: view structure Part 2: Ink view structure Part 3 out of 3 edit structure ... OH SOCI₂ pyridine view structure view structure + SO₂ HCI HO™ CI™ HOCI CI™™ SO₂ HCI U H U + SO₂ + HCI HSO₂Cl O HCI CI™™ HO™ SO₂ HOSC12 HOCI
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![**Be sure to answer all parts.**
**Draw a stepwise mechanism for the following reaction:**
Chemical reaction shown: Conversion of an alcohol group to a chloride using thionyl chloride (SOCl2) and pyridine, resulting in a product with a chlorine atom, plus the byproducts sulfur dioxide (SO2) and hydrogen chloride (HCl).
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**Part 1:**
Diagram showing the reaction step from an alcohol group to the structure involving a new bonded group. Next to it are options for byproducts:
- SO₂
- HCl
- HO⁻
- Cl⁻ (correct option selected)
- HOCl
**Graphical explanation:** The diagram illustrates the initial step where the hydroxyl group is converted, likely forming an intermediate and a chloride ion.
---
**Part 2:**
Diagram showing the reaction step forming a new structure with pyridine in the scheme. Options for products:
- Cl⁻
- SO₂
- HCl
- Pyridine
- HSO₂Cl
**Graphical explanation:** This segment shows the continued reaction with pyridine and the release of sulfur dioxide, suggesting stabilization of the intermediate.
---
**Part 3 out of 3:**
Diagram with a potential error, indicating further reaction to the final product, which includes options for byproducts:
- HCl
- Cl⁻
- HO⁻
- SO₂
- HOSOCl₂
- HOCl
A red box indicates the need for edits or adjustments, likely due to incorrect selections. The structure on the left reacts to yield the final product with a chloride, emphasizing careful byproduct selection.
**Graphical explanation:** This final step confirms the transformation to the target product, focusing on correct byproduct identification from the chemical process shown.
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This problem requires understanding reaction mechanisms, specifically the nucleophilic substitution involving alcohol conversion to chlorides using SOCl₂ and pyridine, and recognizing byproducts at each step.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8ba3a71-d749-40cb-a922-6232b6a4906b%2Fb11b6d6f-e46a-4113-93d2-3b05c5164a95%2F5a3xjm_processed.jpeg&w=3840&q=75)
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