Be A, BY C, three events associated with the same experiment. Suppose they meet the following conditions: P(4) =D 글, P(B) 3D 3, P(C) = , P(ANB) = }, P(AnC) = } y P(BnC) = . 1 1 Р(B) 1 y P(BnC) = 0 6 Calculate P (An (BUC)
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- In a large metropolitan city, the probabilities associated with the number of homicides on any given day are as follows: P(0 homicides)=0.40 P(1 homicide) = 0.25 P(2 homicides) = 0.20 P(3 homicides)= 0.15 In On a randomly selected day, what is the probability of at least one homicide? In What is the probability of no homicides on both of 2 randomly selected days? In What is the probability of at least one homicide in 3 randomly selected days?Suppose A and B are two events with probabilities: P(A°) = .25, P(B) = .35, P(AN B) = .30. a) What is (A|B) ? b) What is (B|A) ?Dr. Ahmed wants to study the relationship between blood pressure and heartbeat irregularities in his patients from the past weeks. He tests a random sample of his patients and notes their blood pressures (high, low, or normal) and their heartbeats (regular or irregular). He finds that: ) 61% have high blood pressure. (i) 14% have low blood pressure. (ii) 24% have an irregular heartbeat. (iv) Of those with an irregular heartbeat, one-third have high blood pressure. (v) Of those with normal blood pressure. one-fifth have an irregular heartbeat. a. What is the percentage of the patients selected have a regular heartbeat and low blood pressure? b. What is the percentage of the patients selected have an irregular heartbeat and normal blood pressure?
- 08 Siti has created a dataset containing 10 rows of data, each row signifies one person. She has two variables, the first is Age (in years) and the other is Cholesterol levels (in mmol/L). She wants to find out if there is any relationship between these two variables using the Pearson correlation in SPSS. a) State the null and alternative hypotheses. b) Based on the Pearson correlation results below from SPSS, make a decision regarding the null hypotheses. Age Pearson Correlation Sig. (2-talled) N Age 1 10 .882 Cholesterol Pearson Correlation Sig. (2-talled) N Correlation is significant at the 0.01 level (2-talled). Cholesterol .882 .001 10 .001 10 1 10An experiment can result in one of five equally likely simple events, E₁, E₂, A: E₂, E4 2' P(A) = = 0.4 B: E₁, E3, E4, E5 P(B) = 0.8 C: E₂, E3 Refer to the following probabilities. P(A n B) = 0.2 P(AIB) = 0.25 P(BIA) P(BU C) = 1 P(BIC) 0.5 P(CIB) 0.25 Use the Addition and Multiplication Rules to find the following probabilities. (a) P(AUB) (b) P(An B) = 0.5 P(A U B) = ---Select--- + ---Select--- ✓ P(A n B) = ---Select--- (c) P(B n C) Yes P(B n C) = ---Select--- No P(C) = 0.4 . P(B) = = P(C) = = ---Select--- V = Do the results agree with those obtained by listing the simple events in each? P(A U B) = P({E₁, E₂, E3, E4, E5}) = 1 P(A n B) = P({E₁}) = 0.2 P(B n C) = P({E3}) = 0.2 .., E5. Events A, B, and C are defined as follows.There are two bags containing several colored balls. The bag B, contains 10 red balls, 12 blue balls, and 13 green balls. The bag B, contains 20 red balls, 19 blue balls and 19 green balls. A student of your class wanted to draw 1 red ball and 3 blue balls. i. If he has the option to draw from only bag B1, what is the probability of drawing the four balls? [Give your answer upto 4 decimal places] ii. If he can choose any bag in an equiprobable manner, what is the probability of drawing the four balls in this case? [Give your answer upto decimal places] 4
- 56.6For independent random variables X and Y, we have var(X -Y) = var(X)-var(Y ). * true FalseA research study was conducted about gender differences in 'sexting'. The researcher believed that the proportion of girls involved in 'sexting' is different from the proportion of boys involved. The data collected in the spring of among a random sample of middle and high school students in a large school district in is summarized next: out of 380 females 43 sent 'sexts' and out of 410 males 64 sent 'sexts'. Is the proportion of girls sending sexts different from the proportion of boys 'sexting'? Choose the appropriate procedure. Procedure: Assumptions: (select everything that applies) Population standard deviations are known Normal populations Sample sizes are both greater than 30 Population standard deviation are unknown but assumed equal Paired samples Population standard deviation are unknown Simple random samples The number of positive and negative responses are both greater than 10 for both samples Independent samples
- I am confused when to use BinomPDF vs. BinomCDF; Find the probability that 17 or more of these 44 randomly-selected burials are babies. I know that from the probability is 13/51, I gathered this from the larger sample of data, however I do not know how to compute "or more"/"or fewer".the answer is not D can i get help pleaseAn "extraneous variable" is not a problem unless it with the independent variable O is identical systematically co-varies is not correlated Wait! An "extraneous variable" is by definition never a problem, that's what "extraneous" means.
