If A and B are two mutually exclusive events with P(A)= 0.5 and P(B)=0.4, find the following probabilities: a) P(A \textrm{ and } B) = 0.2 b) P(A \textrm{ or } B) = c) P( \textrm{not }A ) = d) P( \textrm{not }B ) = e) P( \textrm{not }(A \textrm{ or } B)) = f) P(A and (not B))=
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If A and B are two mutually exclusive
a) P(A \textrm{ and } B) =
0.2
b) P(A \textrm{ or } B) =
c) P( \textrm{not }A ) =
d) P( \textrm{not }B ) =
e) P( \textrm{not }(A \textrm{ or } B)) =
f) P(A and (not B))=
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- Given for independent events A and B are; P(A)=0.25 and P(B)= 0.50 i. determine p(A^B) ii. Draw a Venn diagram to present A and B. fill in the probability of each event depicted in the Venn diagram.The probabilities of events E, F, and EnF are given below. Find (a) P(EIF), (b) P(FIE), (c) P (EIF'), and (d) P (FIE'). 1 P(E) = ₁ P(F) = —, P(ENF) = =1/11 a. P(EIF) = (Type an integer or a simplfied fraction.) b. P(FIE) = (Type an integer or a simplfied fraction.) C. P (EIF') = (Type an integer or a simplified fraction.) d. P (FIE') = (Type an integer or a simplfied fraction.)Q4/ Suppose there are two machines (A, B) in a factory, both producing chairs. Machine A produce twenty percent of their chairs and Machine B produce eighty percent of their chairs. fifteen percent of the chairs come from Machine A are defective and ten percent of the chairs come from Machine B are defective. If a chair is chosen randomly and found to be defective, what is the probability that it came from machine B?
- The probability that Taylor Swift is Austin’s favorite music artist is .10. The probability that he will go to one of her concerts is .84. However, the probability that he does not like Taylor Swift and will go to a concert (because his wife makes him) is .75. a.) Write down the 3 pieces of information given in terms of probabilities involving event A (Taylor Swift is Austin’s favorite music artist) and event B (Austin will go to a Taylor Swift concert). b.) Summarize the above information using a probability table. c.) Find the probability that Taylor Swift is Austin’s favorite music artist or Austin will go to a Taylor Swift concert.✓ 1 ✓2 Part 1 of 4 Part 2 of 4 = 3 Question Attempt: 1 of 1 Continue 47°F Cloudy = 4 = 5 = 6 (a) What is the probability that five or more of them used their phones for guidance on purchasing decisions? The probability that five or more of them used their phones for guidance on purchasing decisions is G = 7 8 What should I buy? A study conducted by a research group in a recent year reported that 56% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 13 cell phone owners is studied. Round the answers to at least four decimal places. Q Search (b) What is the probability that fewer than nine of them used their phones for guidance on purchasing decisions? 9 10 DELL 11 X 12 5 13 Save For Later © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Babith E D 198 M olo 6 Submit Assignment Privacy Center | Accessibility 12:42 3/26/2Hamza comes to office located in Islamabad through different modes of transport. From his past data, itis known that the probability of him coming through car, bus, motorbike and rickshaw are respectively 3/10,1/5,1/10,2/5The probabilities that he will arrive to his office late are 1/4,1/3,1/12 if he comes bycar, bus and motorbike. Interestingly, he will not be late if he comes by rickshaw. Suppose, he arriveslate on Friday. What is the probability that he came by car?
- 5. A candy dish contains 2 red (R) and 4 yellow (Y) candies. You close your eyes, select two candies from the dish (without replacement), and record their colors. Use general multiplication rule and special addition rule to find the following probabilities. a. The probability that the first selected candy will be red and the second selected candy will be yellow is b. The probability that two selected candies will be of different colors_ One is red, another one is yellow c. Probability that two selected candies will be of the same color_ Both are red or both are yellow Assuming that the event "The first selected candy will be red and the second selected candy will be yellow "is denoted by A, the event "Two selected candies will be of different colors" is denoted by B, and the event "Two selected candies will be of the same color" is denoted by C, show your work in finding P(A), P(B), and P(C) in the questions a, b, and c.Suppose there are 6 red balls and 4 white balls in a urn.(1) event A={First draw is a white ball}, what is P(A), probability of A?(2) Now assume we do picking balls one by one without replacement. event B={Second draw is a white ball}, what is P(B), probability of B? (3) Are A and B independent? Justify your answer. please explain and do all the steps fully!Suppose A and B are two events with probabilities: P(A^c)=.30, P(B/A)=.40 What is (AnB)?
- Determine all joint probabilities listed below from the following information: SP(A)=0.7, P\left(A^{c}\right)=0.3, P(B \mid A)=0.37, P\left(B \mid A^{c}\right)=0.74$ $P(A$ and $B)=$ SP\left(A\right.$ and $\left.B^{c}\right)=$ SP\left(A^{c}\right.$ and $\left.B\right)=$ SP\left(A^{c}\right.$ and $\left.B^{c}\right)=$ SP.PC.066|Data from Office on Smoking and Health, Centers for Disease Control and Prevention, indicate that 35% of adults who did not finish high school, 33% of high school graduates, 22% of adults who completed some college, and 12% of college graduates smoke. Suppose that one individual is selected at random and it is discovered that the individual smokes. Use the probabilities in the following table to calculate the probability that the individual is a college graduate. Education Not a high school graduate 0.0975 High school graduate Some college, no degree Employed Unemployed 0.0080 Associate Degree Bachelor Degree Advanced Degree 0.3108 0.1785 0.0849 0.1959 0.0975 0.0128 0.0062 0.0023 0.0041 0.0015 Probability = | proportion of Hints: This problem has all the information you need, but not in the typical ready-to-use form. The table above can tell you t people with various levels of education in the population. Keep in mind that any degree (Associate, Bachelor, or Advanced) counts as…Suppose one NBA player can get one point in each free shot with probability 0.8. Now he has five times of free shots and it is reasonable to assume that the result in each shot has no impact on other shots. (b) What is the probability of his getting 3 points?(c) What is the probability of his getting at least 2 points?(d) we define an unusual event if the chance of the event is below 5%. Is it an unusual event that he lost all his shots? please explain each step fully
