Two fair 6-sided dice are rolled. Let A = the event that the dice add to 6, and let B = the event that the dice add to an odd number. Find P(A/B) and P(A/B). P(A/B) = (Simplify your answer.) P(AIB') = (Simplify your answer.)

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**Title: Probability Calculation for Rolling Two Fair 6-Sided Dice**

**Description:**
In this example, we are rolling two fair 6-sided dice and examining two specific events:
- **Event A**: The sum of the numbers on the two dice equals 6.
- **Event B**: The sum of the numbers on the two dice is an odd number.

We aim to find the conditional probability \( P(A|B) \) and the conditional probability \( P(A|B') \), where \( B' \) represents the complement of event B (i.e., the sum of the numbers is not odd, which means it is even).

### Probability Solutions:

**1. Calculate \( P(A|B) \):**
\[ P(A|B) = \text{[Input required]} \]
(Simplify your answer.)

**2. Calculate \( P(A|B') \):**
\[ P(A|B') = \text{[Input required]} \]
(Simplify your answer.)

---

### Explanation:

- **Event A (Sum equals 6)**: Possible pairs (Dice 1, Dice 2) that result in this event are:
    - (1, 5)
    - (2, 4)
    - (3, 3)
    - (4, 2)
    - (5, 1)

- **Event B (Sum is an odd number)**: Possible pairs (Dice 1, Dice 2) that result in this event include:
    - (1, 2), (1, 4), (1, 6)
    - (2, 1), (2, 3), (2, 5)
    - (3, 2), (3, 4), (3, 6)
    - (4, 1), (4, 3), (4, 5)
    - (5, 2), (5, 4), (5, 6)
    - (6, 1), (6, 3), (6, 5)

- **Event \( B' \) (Sum is an even number)**: All other pairs where the sum is even.

**Note**: Students must find the simplified probabilities by considering the number of favorable outcomes for each event and the relevant conditional probabilities.

**Related Concepts:**
- Basic Probability Rules
- Conditional Probability
- Independent Events
Transcribed Image Text:**Title: Probability Calculation for Rolling Two Fair 6-Sided Dice** **Description:** In this example, we are rolling two fair 6-sided dice and examining two specific events: - **Event A**: The sum of the numbers on the two dice equals 6. - **Event B**: The sum of the numbers on the two dice is an odd number. We aim to find the conditional probability \( P(A|B) \) and the conditional probability \( P(A|B') \), where \( B' \) represents the complement of event B (i.e., the sum of the numbers is not odd, which means it is even). ### Probability Solutions: **1. Calculate \( P(A|B) \):** \[ P(A|B) = \text{[Input required]} \] (Simplify your answer.) **2. Calculate \( P(A|B') \):** \[ P(A|B') = \text{[Input required]} \] (Simplify your answer.) --- ### Explanation: - **Event A (Sum equals 6)**: Possible pairs (Dice 1, Dice 2) that result in this event are: - (1, 5) - (2, 4) - (3, 3) - (4, 2) - (5, 1) - **Event B (Sum is an odd number)**: Possible pairs (Dice 1, Dice 2) that result in this event include: - (1, 2), (1, 4), (1, 6) - (2, 1), (2, 3), (2, 5) - (3, 2), (3, 4), (3, 6) - (4, 1), (4, 3), (4, 5) - (5, 2), (5, 4), (5, 6) - (6, 1), (6, 3), (6, 5) - **Event \( B' \) (Sum is an even number)**: All other pairs where the sum is even. **Note**: Students must find the simplified probabilities by considering the number of favorable outcomes for each event and the relevant conditional probabilities. **Related Concepts:** - Basic Probability Rules - Conditional Probability - Independent Events
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