O The function h(x) is undefined at the values x= -2, and -1 in the table.O The graph is increasing to the right of the origin (0,0) and will go to positive infinity as the function moves right.For the functionh (x) = Vr, if the input is negative then the output will not be a real number. Also, h (x) = VI willonly produce positive outputs for x>0. The only quadrant outputs can exist in for x>0 is Quadrant 1.%3DO All of the above statements are correct justifications for the summary statement.14Type here to search3.近 BCPS LinksWhich one of the justifications for the summary statement below does not justify the statement accurately.Summary Statement: The function h (x)Væ will not go through Quadrants 2, 3, and 4.10-N h(x)-2undefined5--1undefined11-5104-5-9.3164The function h(x) is undefined at the values x= -2, and -1 in the table.O Type here to search2.近

BCPS Links Which one of the justifications for the summary statement below does not justify the statement accurately. Summary Statement: The function h (x) Væ will not go through Quadrants 2, 3, and 4. 10- N h(x) -2 undefined 5- -1 undefined 0. 1 1 -5 0. 10 4 -5- 9. 3 16 4 The function h(x) is undefined at the values x= -2, and -1 in the table. O Type here to search 2. 近 LO

BCPS Links Which one of the justifications for the summary statement below does not justify the statement accurately. Summary Statement: The function h (x) Væ will not go through Quadrants 2, 3, and 4. 10- N h(x) -2 undefined 5- -1 undefined 0. 1 1 -5 0. 10 4 -5- 9. 3 16 4 The function h(x) is undefined at the values x= -2, and -1 in the table. O Type here to search 2. 近 LO

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

100%

O The function h(x) is undefined at the values x= -2, and -1 in the table.
O The graph is increasing to the right of the origin (0,0) and will go to positive infinity as the function moves right.
For the functionh (x) = Vr, if the input is negative then the output will not be a real number. Also, h (x) = VI will
only produce positive outputs for x>0. The only quadrant outputs can exist in for x>0 is Quadrant 1.
%3D
O All of the above statements are correct justifications for the summary statement.
1
4
Type here to search
3.
近

BCPS Links
Which one of the justifications for the summary statement below does not justify the statement accurately.
Summary Statement: The function h (x)
Væ will not go through Quadrants 2, 3, and 4.
10-
N h(x)
-2
undefined
5-
-1
undefined
1
1
-5
10
4
-5-
9.
3
16
4
The function h(x) is undefined at the values x= -2, and -1 in the table.
O Type here to search
2.
近

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