Given a and f(x), fill out the rest of the table.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I need help filling out the rest of this table after been given the x and f(x) values

**Instructions:**

Given \( x \) and \( f(x) \), fill out the rest of the table.

**Table:**

\[
\begin{array}{|c|c|c|c|c|c|}
\hline
x & -2 & -1 & 0 & 1 & 2 \\
\hline
f(x) & -5 & 1 & 5 & 8 & 10 \\
\hline
f(x) - 1 & -6 & \, & \, & \, & 9 \\
\hline
f(x-1) & -7 & \, & \, & \, & 8 \\
\hline
-f(x) & 5 & \, & \, & \, & -10 \\
\hline
f(-x) & 10 & \, & \, & \, & -5 \\
\hline
\end{array}
\]

**Note:**
- The first row \( x \) contains input values.
- The second row \( f(x) \) lists corresponding output values for each \( x \).
- The subsequent rows represent transformations or variations of the function \( f(x) \):
  - \( f(x) - 1\) subtracts 1 from each \( f(x) \) value.
  - \( f(x-1) \) evaluates \( f \) at \( x-1 \).
  - \(-f(x)\) negates each \( f(x) \) value.
  - \( f(-x) \) evaluates \( f \) at the negation of each \( x \) value.
Transcribed Image Text:**Instructions:** Given \( x \) and \( f(x) \), fill out the rest of the table. **Table:** \[ \begin{array}{|c|c|c|c|c|c|} \hline x & -2 & -1 & 0 & 1 & 2 \\ \hline f(x) & -5 & 1 & 5 & 8 & 10 \\ \hline f(x) - 1 & -6 & \, & \, & \, & 9 \\ \hline f(x-1) & -7 & \, & \, & \, & 8 \\ \hline -f(x) & 5 & \, & \, & \, & -10 \\ \hline f(-x) & 10 & \, & \, & \, & -5 \\ \hline \end{array} \] **Note:** - The first row \( x \) contains input values. - The second row \( f(x) \) lists corresponding output values for each \( x \). - The subsequent rows represent transformations or variations of the function \( f(x) \): - \( f(x) - 1\) subtracts 1 from each \( f(x) \) value. - \( f(x-1) \) evaluates \( f \) at \( x-1 \). - \(-f(x)\) negates each \( f(x) \) value. - \( f(-x) \) evaluates \( f \) at the negation of each \( x \) value.
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