Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20  kg of water to go from -14.0 °C to 74.0 °C.

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Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20  kg of water to go from -14.0 °C to 74.0 °C. 
 

 

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Answer was incorrect, but i tried plugging in other values for Cp and they didn't work, is there another step to the problem

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**5th Attempt: Calculating Energy Requirement for Temperature Change of Water**

Based on the thermodynamic properties provided for water, calculate the amount of energy needed for 2.20 kg of water to change from -14.0 °C to 74.0 °C.

**Thermodynamic Properties Table:**

| Property       | Value | Units       |
|----------------|-------|-------------|
| Melting point  | 0.0   | °C          |
| Boiling point  | 100.0 | °C          |
| ΔH_fus         | 6.01  | kJ/mol      |
| ΔH_vap         | 40.67 | kJ/mol      |
| c_p (s)        | 37.1  | J/mol·°C    |
| c_p (l)        | 75.3  | J/mol·°C    |
| c_p (g)        | 33.6  | J/mol·°C    |

**Explanation:**

- **Melting Point:** The temperature at which ice turns to liquid water (0.0 °C).
- **Boiling Point:** The temperature at which liquid water turns to steam (100.0 °C).
- **ΔH_fus (Heat of Fusion):** Energy needed to change ice to liquid water at the melting point (6.01 kJ/mol).
- **ΔH_vap (Heat of Vaporization):** Energy needed to turn liquid water to vapor at the boiling point (40.67 kJ/mol).
- **c_p (s, l, g):** Specific heat capacities for solid (ice), liquid, and gas (steam) states, measured in J/mol·°C.

To find the total energy, consider the heat required for warming ice, melting, heating water, and if necessary, vaporizing into steam.

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Transcribed Image Text:--- **5th Attempt: Calculating Energy Requirement for Temperature Change of Water** Based on the thermodynamic properties provided for water, calculate the amount of energy needed for 2.20 kg of water to change from -14.0 °C to 74.0 °C. **Thermodynamic Properties Table:** | Property | Value | Units | |----------------|-------|-------------| | Melting point | 0.0 | °C | | Boiling point | 100.0 | °C | | ΔH_fus | 6.01 | kJ/mol | | ΔH_vap | 40.67 | kJ/mol | | c_p (s) | 37.1 | J/mol·°C | | c_p (l) | 75.3 | J/mol·°C | | c_p (g) | 33.6 | J/mol·°C | **Explanation:** - **Melting Point:** The temperature at which ice turns to liquid water (0.0 °C). - **Boiling Point:** The temperature at which liquid water turns to steam (100.0 °C). - **ΔH_fus (Heat of Fusion):** Energy needed to change ice to liquid water at the melting point (6.01 kJ/mol). - **ΔH_vap (Heat of Vaporization):** Energy needed to turn liquid water to vapor at the boiling point (40.67 kJ/mol). - **c_p (s, l, g):** Specific heat capacities for solid (ice), liquid, and gas (steam) states, measured in J/mol·°C. To find the total energy, consider the heat required for warming ice, melting, heating water, and if necessary, vaporizing into steam. ---
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