Question 6 ( A closed system having a weight of 85 lbs. has an initial velocity of 30 ft/s. Its velocity is increased to 80 ft/s and its elevation is increased by 122 ft. During the process, the system received 75 Btu of heat and 2800 ft-lb of work and delivers 0.02 kWh of electrical energy. Determine the change in internal energy of the system. -15.95 Btu -5.65 Btu -12.33 Btu -9.50 Btu

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A: Given:  Work done, W = 325 kcal = 325 x 4.18 kJ = 1358.5 kJ As there are 4.18 J in one cal.  heat…

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A: 1.GivenWork is done on the system , W=-360 JIncrease in internal energy, ∆U=180 J

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