Based on the nutrition facts of a famous brand of potato chips, its average sodium content is 85 mg per serving (1 bag) with a standard deviation of 2.2 mg. Sixty-four (64) bags were taken as sample. Assume that the variable is normally distributed. Prompts Submitted Answers What is the mean of the sampling distribution? 85 Find the standard error of the sampling 0.275 distribution of the sample mean. Using the central limit theorem, 0.0018 find the probability that the average sodium content will be larger than 85.8 mg? Find the range of values where Choose a match the middle 80% of the distribution of sample means will lie (A to B). The value of A is Choose a match Following the range of values problem (middle 80%), the value of Bis Ⓒ

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Based on the nutrition facts of a famous brand of potato chips, its average sodium
content is 85 mg per serving (1 bag) with a standard deviation of 2.2 mg. Sixty-four (64)
bags were taken as sample. Assume that the variable is normally distributed.
Prompts
Submitted Answers
What is the mean of the sampling distribution?
85
Find the standard error of the sampling
0.275
distribution of the sample mean.
Using the central limit theorem,
0.0018
find the probability that the average
sodium content will be larger than 85.8 mg?
Find the range of values where
Choose a match
the middle 80% of the distribution of
sample means will lie (A to B).
The value of A is
Choose a match
Following the range of values
problem (middle 80%), the value
of Bis
Transcribed Image Text:Based on the nutrition facts of a famous brand of potato chips, its average sodium content is 85 mg per serving (1 bag) with a standard deviation of 2.2 mg. Sixty-four (64) bags were taken as sample. Assume that the variable is normally distributed. Prompts Submitted Answers What is the mean of the sampling distribution? 85 Find the standard error of the sampling 0.275 distribution of the sample mean. Using the central limit theorem, 0.0018 find the probability that the average sodium content will be larger than 85.8 mg? Find the range of values where Choose a match the middle 80% of the distribution of sample means will lie (A to B). The value of A is Choose a match Following the range of values problem (middle 80%), the value of Bis
85
85.35
0.0018
85.23
84.77
0.9982
83.15
0.275
84.65
85.8
0.034
Transcribed Image Text:85 85.35 0.0018 85.23 84.77 0.9982 83.15 0.275 84.65 85.8 0.034
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