The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.21°F and astandard deviation of 0.49°F. Using the empirical rule, find each approximate percentage below.a. What is the approximate percentage of healthy adults with body temperatures within 2 standard deviations of themean, or between 97.23°F and 99.19°F?b. What is the approximate percentage of healthy adults with body temperatures between 97.72°F and 98.70°F?CAFERECEMa. Approximately % of healthy adults in this group have body temperatures within 2 standard deviations of the mean,or between 97.23°F and 99.19°F.(Type an integer or a decimal. Do not round.)b. Approximately % of healthy adults in this group have body temperatures between 97.72°F and 98.70°F.(Type an integer or a decimal. Do not round.)BITIYouTubeDinomania

Given that Mean = 98.21 , Standard deviation = 0.49 X ~ N(μ = 98.21, σ = 0.49)

Answered: e body temperatures of a group of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 72.6 Mbps. The complete list of 50 data speeds has a mean of x=18.29 Mbps and a standard deviation of s=19.75 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? Question content area bottom Part 1 a. The difference is 54.3154.31 Mbps. (Type an integer or a decimal. Do not round.) Part 2 b. The difference is enter your response here standard deviations. (Round to two decimal places as needed.)
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