Based on the Kf values listed in table 17.1, calculate the concentration of NH3 required to dissolve 0.020 moles of NiC2O4 (Ksp = 4*10-10) in 1.00 L of solution.  You can neglect the hydrolysis of C2O42- because the solution will be basic.

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Based on the Kf values listed in table 17.1, calculate the concentration of NH3 required to dissolve 0.020 moles of NiC2O4 (Ksp = 4*10-10) in 1.00 L of solution.  You can neglect the hydrolysis of C2O42- because the solution will be basic.  

TABLE 17.1 Formation Constants for Some Metal Complex Ions
in Water at 25 °C
Complex lon
Chemical Equation
Ag(NH3)2*
1.7 x 107
Ag*(aq) + 2 NH3(aq)
Ag(NH3)2* (aq)
Ag(CN)2
1 × 10²1
Ag*(aq) + 2 CN (aq) = Ag(CN), (aq)
3-
Ag(S,O3)
2.9 x 1013
Ag*(aq) + 2 S20-(aq)
Ag(S,O3)- (ag)
Al(OH)4
1.1 × 1033
Al3+ (aq) + 4 OH (aq) = Al(OH)4¯(aq)
CdBr?-
5 x 103
Cd² *(aq) + 4 Br (aq) CdBr? (aq)
:-
Cr(OH)4
8 x 1029
Cr3+(aq) + 4 OH (aq)
Cr(OH) (aq)
Co(SCN),?-
1 x 103
Co2*(aq) + 4 SCN (aq)
Co(SCN)?- (aq)
2+
Cu(NH3)?*
5 x 1012
Cu²+(aq) + 4 NH3 (aq) = Cu(NH3)2* (aq)
Cu(CN),?-
1 x 1025
Cu² *(aq) + 4 CN (aq)
2 Cu(CN),+ (aq)
Ni(NH3),*
2+
1.2 x 10°
Ni²*(aq) + 6 NH3 (aq) = Ni(NH3),²* (aq)
Fe(CN),
Fe(CN), (aq)
4-
4-
1 x 1035
Fe2*(aq) + 6 CN (aq)
Fe(CN),-
1 x 1042
Fe*(aq) + 6 CN (aq) = Fe(CN),- (aq)
Zn(OH),-
4.6 x 1017
Zn2*(aq) + 4 OH (aq) = Zn(OH),- (aq)
Transcribed Image Text:TABLE 17.1 Formation Constants for Some Metal Complex Ions in Water at 25 °C Complex lon Chemical Equation Ag(NH3)2* 1.7 x 107 Ag*(aq) + 2 NH3(aq) Ag(NH3)2* (aq) Ag(CN)2 1 × 10²1 Ag*(aq) + 2 CN (aq) = Ag(CN), (aq) 3- Ag(S,O3) 2.9 x 1013 Ag*(aq) + 2 S20-(aq) Ag(S,O3)- (ag) Al(OH)4 1.1 × 1033 Al3+ (aq) + 4 OH (aq) = Al(OH)4¯(aq) CdBr?- 5 x 103 Cd² *(aq) + 4 Br (aq) CdBr? (aq) :- Cr(OH)4 8 x 1029 Cr3+(aq) + 4 OH (aq) Cr(OH) (aq) Co(SCN),?- 1 x 103 Co2*(aq) + 4 SCN (aq) Co(SCN)?- (aq) 2+ Cu(NH3)?* 5 x 1012 Cu²+(aq) + 4 NH3 (aq) = Cu(NH3)2* (aq) Cu(CN),?- 1 x 1025 Cu² *(aq) + 4 CN (aq) 2 Cu(CN),+ (aq) Ni(NH3),* 2+ 1.2 x 10° Ni²*(aq) + 6 NH3 (aq) = Ni(NH3),²* (aq) Fe(CN), Fe(CN), (aq) 4- 4- 1 x 1035 Fe2*(aq) + 6 CN (aq) Fe(CN),- 1 x 1042 Fe*(aq) + 6 CN (aq) = Fe(CN),- (aq) Zn(OH),- 4.6 x 1017 Zn2*(aq) + 4 OH (aq) = Zn(OH),- (aq)
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