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Based on the given pK, values, determine which compound would form the weaker base upon deprotonation. Select the single best answer. O pK₂=14 H pK₂ = 19 X

Based on the given pK, values, determine which compound would form the weaker base upon deprotonation. Select the single best answer. O pK₂=14 H pK₂ = 19 X

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Exercise: Determining the Weaker Base Upon Deprotonation **Objective:** Based on the given \( pK_a \) values, determine which compound would form the weaker base upon deprotonation. Select the single best answer. #### Compounds: 1. **Compound 1:** - Structure: Aldehyde with a hydrogen bound to the carbonyl carbon \((\text{C}= \text{O})\). - \( pK_a = 14 \) 2. **Compound 2:** - Structure: Ketone with a methyl group bound to the carbonyl carbon \((\text{C}=\text{O})\). - \( pK_a = 19 \) **Conclusion:** The compound with the lower \( pK_a \) value forms the stronger acid, which means its conjugate base will be weaker. Therefore, Compound 1, with a \( pK_a \) of 14, forms the weaker base upon deprotonation than Compound 2, with a \( pK_a \) of 19.
Transcribed Image Text:### Exercise: Determining the Weaker Base Upon Deprotonation **Objective:** Based on the given \( pK_a \) values, determine which compound would form the weaker base upon deprotonation. Select the single best answer. #### Compounds: 1. **Compound 1:** - Structure: Aldehyde with a hydrogen bound to the carbonyl carbon \((\text{C}= \text{O})\). - \( pK_a = 14 \) 2. **Compound 2:** - Structure: Ketone with a methyl group bound to the carbonyl carbon \((\text{C}=\text{O})\). - \( pK_a = 19 \) **Conclusion:** The compound with the lower \( pK_a \) value forms the stronger acid, which means its conjugate base will be weaker. Therefore, Compound 1, with a \( pK_a \) of 14, forms the weaker base upon deprotonation than Compound 2, with a \( pK_a \) of 19.
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