**Balancing and Problem Solving with Chemical Equations****Balance the following equations and solve the accompanying problems using dimensional analysis.**1. **Calculate the moles of solid formed from 2.652 moles HBr.** \[ \_\_ \text{FeS(s)} + \_\_ \text{HBr(aq)} \rightarrow \_\_ \text{FeBr}_2\text{(s)} + \_\_ \text{H}_2\text{S(g)} \]2. **Calculate the number of nitrogen molecules formed from 1.30 mol of NaN\(_3\).** \[ \_\_ \text{NaN}_3\text{(s)} \rightarrow \_\_ \text{N}_2\text{(g)} + \_\_ \text{Na(s)} \]3. **Calculate the number of oxygen molecules needed to react with 1.00 g of manganese.** \[ \_\_ \text{Mn(s)} + \_\_ \text{O}_2\text{(g)} \rightarrow \_\_ \text{Mn}_3\text{O}_4\text{(s)} \]**Instructions:**- Identify and balance each chemical equation.- Use stoichiometry to solve each problem utilizing dimensional analysis. This includes converting moles of reactants to moles of products and utilizing molar masses where necessary.

Since, Balanced reaction means that both side number of atom present in equal number. Thus,

Balance the following equations and solve the following problems using dimensional analysis. 1. Calculate the moles of solid formed from 0.652 moles HBr. FeS(s) + HBr(aq) → FeBr2(s) + H₂S(g) 2. Calculate the number of nitrogen molecules formed from 1.30 mol of NaN3. _NaN3(s)→ N2(g) + __Na(s) 3. Calculate the number of oxygen molecules needed to react with 1.00 g of manganese. Mn(s) + _O2(g) → Mn304(s)

Balance the following equations and solve the following problems using dimensional analysis. 1. Calculate the moles of solid formed from 0.652 moles HBr. FeS(s) + HBr(aq) → FeBr2(s) + H₂S(g) 2. Calculate the number of nitrogen molecules formed from 1.30 mol of NaN3. _NaN3(s)→ N2(g) + __Na(s) 3. Calculate the number of oxygen molecules needed to react with 1.00 g of manganese. Mn(s) + _O2(g) → Mn304(s)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

**Balancing and Problem Solving with Chemical Equations**

**Balance the following equations and solve the accompanying problems using dimensional analysis.**

1. **Calculate the moles of solid formed from 2.652 moles HBr.**
\[
\_\_ \text{FeS(s)} + \_\_ \text{HBr(aq)} \rightarrow \_\_ \text{FeBr}_2\text{(s)} + \_\_ \text{H}_2\text{S(g)}
\]

2. **Calculate the number of nitrogen molecules formed from 1.30 mol of NaN\(_3\).**
\[
\_\_ \text{NaN}_3\text{(s)} \rightarrow \_\_ \text{N}_2\text{(g)} + \_\_ \text{Na(s)}
\]

3. **Calculate the number of oxygen molecules needed to react with 1.00 g of manganese.**
\[
\_\_ \text{Mn(s)} + \_\_ \text{O}_2\text{(g)} \rightarrow \_\_ \text{Mn}_3\text{O}_4\text{(s)}
\]

**Instructions:**
- Identify and balance each chemical equation.
- Use stoichiometry to solve each problem utilizing dimensional analysis. This includes converting moles of reactants to moles of products and utilizing molar masses where necessary.

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