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Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients. Ca, (PO), (s) + SiO₂ (s) + C(s) → CaSiO₂ (s) + P(s) + CO(g) 1 X ?

Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients. Ca, (PO), (s) + SiO₂ (s) + C(s) → CaSiO₂ (s) + P(s) + CO(g) 1 X ?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Balancing Chemical Equations: An Example** Chemical equations represent the reactants and products in a chemical reaction. To adhere to the Law of Conservation of Mass, these equations must be balanced, meaning the same number of atoms for each element must be present on both sides of the equation. Here is an example of balancing a chemical equation: **Prompt:** Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients: \[ \text{Ca}_3(\text{PO}_4)_2 (\text{s}) + \text{SiO}_2 (\text{s}) + \text{C} (\text{s}) \rightarrow \text{CaSiO}_3 (\text{s}) + \text{P}_4 (\text{s}) + \text{CO} (\text{g}) \] **Explanation:** To balance this equation, follow these steps: 1. **Identify each element in the equation.** 2. **Tally the number of atoms of each element in both the reactants and products.** Reactants: - \( \text{Ca}_3(\text{PO}_4)_2 \): - \(\text{Ca}=3, \text{P}=2, \text{O}=8\) - \(\text{SiO}_2\): - \(\text{Si}=1, \text{O}=2\) - \(\text{C}\): - \(\text{C}=1\) Products: - \(\text{CaSiO}_3\): - \(\text{Ca}=1, \(\text{Si}=1, \(\text{O}=3\) - \(\text{P}_4\): - \(\text{P}=4\) - \(\text{CO}\): - \(\text{C}=1, \(\text{O}=1\) 3. **Balance one element at a time by adjusting coefficients.** Use the smallest possible whole numbers as coefficients. - Balance Calcium (Ca): \[ \text{Ca}_3(\text{PO}_4)_2: \text{Ca}=3 \rightarrow 3\text{CaSiO}_3: \text{Ca}=3 \] - Balance Phosphorus (P): \[ \text
Transcribed Image Text:**Balancing Chemical Equations: An Example** Chemical equations represent the reactants and products in a chemical reaction. To adhere to the Law of Conservation of Mass, these equations must be balanced, meaning the same number of atoms for each element must be present on both sides of the equation. Here is an example of balancing a chemical equation: **Prompt:** Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients: \[ \text{Ca}_3(\text{PO}_4)_2 (\text{s}) + \text{SiO}_2 (\text{s}) + \text{C} (\text{s}) \rightarrow \text{CaSiO}_3 (\text{s}) + \text{P}_4 (\text{s}) + \text{CO} (\text{g}) \] **Explanation:** To balance this equation, follow these steps: 1. **Identify each element in the equation.** 2. **Tally the number of atoms of each element in both the reactants and products.** Reactants: - \( \text{Ca}_3(\text{PO}_4)_2 \): - \(\text{Ca}=3, \text{P}=2, \text{O}=8\) - \(\text{SiO}_2\): - \(\text{Si}=1, \text{O}=2\) - \(\text{C}\): - \(\text{C}=1\) Products: - \(\text{CaSiO}_3\): - \(\text{Ca}=1, \(\text{Si}=1, \(\text{O}=3\) - \(\text{P}_4\): - \(\text{P}=4\) - \(\text{CO}\): - \(\text{C}=1, \(\text{O}=1\) 3. **Balance one element at a time by adjusting coefficients.** Use the smallest possible whole numbers as coefficients. - Balance Calcium (Ca): \[ \text{Ca}_3(\text{PO}_4)_2: \text{Ca}=3 \rightarrow 3\text{CaSiO}_3: \text{Ca}=3 \] - Balance Phosphorus (P): \[ \text
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