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BALANCE REDOX REACTION (USE THE LONG METHOD WITH CHECKINGS) SO2 + O2 → SO3 CONTENT SHOULD BE THESE OXIDIZED REDUCED BASIC SOLUTION CHECKING

BALANCE REDOX REACTION (USE THE LONG METHOD WITH CHECKINGS) SO2 + O2 → SO3 CONTENT SHOULD BE THESE OXIDIZED REDUCED BASIC SOLUTION CHECKING

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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BALANCE REDOX REACTION (USE THE LONG METHOD WITH CHECKINGS) SO₂ + O2SO3 CONTENT SHOULD BE THESE OXIDIZED REDUCED BASIC SOLUTION CHECKING ( 3) AI + NO₂ → Al +5+₂=1 ↑ +4 -4 =0 ↑ +4-2 +2 +5-2 Al + NO ₂ → A1 ²+ + NO₂ √ oxidized: oxidized, reduced, oxidizing agent reducing agent A1 A1²+ + 2 e A):1 +2-2=0 ducking Al: 1 #:4 V 2 +4-2=+2 2+ BASIC SOLUTION + NO₂ AL: 1 6 Al212e 2e + 4H+ + 2NO₂ → 2ND ₂ + 2H₂P 2 AL + 2 + 4H+ + 2NO₂ → A1 ²+ + 2√² + 2NO₂ + 2H₂O | Al + 4H+ + 2 NO₂ →→ A1²+ + 2NO₂ + 2H₂O Balanced in acidic solution 0216=8 N₁2 -2 Al: T H:4 N÷2 0²4+2=6 +2 Reduced: e²+ 2H+ + NO₂ → NO ₂ + H₂D N = 1 0.83 H: 2 O N=1 0:3 H.2 +24-H-E01 AL + 4H+ + 2NO3 → A1²+ + 2NO₂ + 2H₂O Al + 4H+ + 40 H ¯ + 2 NO ₂- → A1²+ + 2NO₂ + 2H₂0 + 40H- Al + ₂ + 2 NO₂ → A1 ²+ + 2NO₂ + 2H₂Q + 40H- Date : 2e + 2H+ NO₂ NO ₂ + H₂0) -7 2e + 4H+ + 2NO3 -> 2ND ₂ + 2H₂O 2 Al + 2H₂O + 2NO3 →→ A1²+ + 2NO₂ + 40μ - Balanced in basic solution clacking: A1 = 1 Al: H:4 0²4+4=8 N÷2 +2-4 = -2 VICTORY
Transcribed Image Text:BALANCE REDOX REACTION (USE THE LONG METHOD WITH CHECKINGS) SO₂ + O2SO3 CONTENT SHOULD BE THESE OXIDIZED REDUCED BASIC SOLUTION CHECKING ( 3) AI + NO₂ → Al +5+₂=1 ↑ +4 -4 =0 ↑ +4-2 +2 +5-2 Al + NO ₂ → A1 ²+ + NO₂ √ oxidized: oxidized, reduced, oxidizing agent reducing agent A1 A1²+ + 2 e A):1 +2-2=0 ducking Al: 1 #:4 V 2 +4-2=+2 2+ BASIC SOLUTION + NO₂ AL: 1 6 Al212e 2e + 4H+ + 2NO₂ → 2ND ₂ + 2H₂P 2 AL + 2 + 4H+ + 2NO₂ → A1 ²+ + 2√² + 2NO₂ + 2H₂O | Al + 4H+ + 2 NO₂ →→ A1²+ + 2NO₂ + 2H₂O Balanced in acidic solution 0216=8 N₁2 -2 Al: T H:4 N÷2 0²4+2=6 +2 Reduced: e²+ 2H+ + NO₂ → NO ₂ + H₂D N = 1 0.83 H: 2 O N=1 0:3 H.2 +24-H-E01 AL + 4H+ + 2NO3 → A1²+ + 2NO₂ + 2H₂O Al + 4H+ + 40 H ¯ + 2 NO ₂- → A1²+ + 2NO₂ + 2H₂0 + 40H- Al + ₂ + 2 NO₂ → A1 ²+ + 2NO₂ + 2H₂Q + 40H- Date : 2e + 2H+ NO₂ NO ₂ + H₂0) -7 2e + 4H+ + 2NO3 -> 2ND ₂ + 2H₂O 2 Al + 2H₂O + 2NO3 →→ A1²+ + 2NO₂ + 40μ - Balanced in basic solution clacking: A1 = 1 Al: H:4 0²4+4=8 N÷2 +2-4 = -2 VICTORY
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