Bags of a certain brand of tortilla chips claim to have a net weight of 14 ounces. Net weights actually vary slightly from bag to bag. Assume net weights are Normally distributed. A representative of a consumer advocate group wishes to see if there is any evidence that the mean net weight is less than advertised and so intends to test the hypotheses Ho: µ= 14 versus Ha: µ<14. To do this, he selects 16 bags of tortilla chips of this brand at random and determines the net weight of each. He finds a sample mean of 13.88 ounces with a standard deviation of s = 0.24 ounces. What is the value of the test statistic? A) t=-0.50 B) t=-2.00 C) t=-8.00 D) t=-8.33

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Bags of a certain brand of tortilla chips claim to have a net weight of 14 ounces. Net
weights actually vary slightly from bag to bag. Assume net weights are Normally
distributed. A representative of a consumer advocate group wishes to see if there is any
evidence that the mean net weight is less than advertised and so intends to test the
hypotheses Ho: µ= 14 versus Ha: µ<14. To do this, he selects 16 bags of tortilla chips
of this brand at random and determines the net weight of each. He finds a sample mean
of 13.88 ounces with a standard deviation of s
test statistic?
0.24 ounces. What is the value of the
A) t=-0.50
В) t%3D-2.00
C) t=-8.00
D) t=-8.33
Transcribed Image Text:Bags of a certain brand of tortilla chips claim to have a net weight of 14 ounces. Net weights actually vary slightly from bag to bag. Assume net weights are Normally distributed. A representative of a consumer advocate group wishes to see if there is any evidence that the mean net weight is less than advertised and so intends to test the hypotheses Ho: µ= 14 versus Ha: µ<14. To do this, he selects 16 bags of tortilla chips of this brand at random and determines the net weight of each. He finds a sample mean of 13.88 ounces with a standard deviation of s test statistic? 0.24 ounces. What is the value of the A) t=-0.50 В) t%3D-2.00 C) t=-8.00 D) t=-8.33
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