B. For data type double, what lower bound on the CPE is determined by the critical path? C. Assuming similar instruction sequences for the integer code as well, what lower bound on the CPE is determined by the critical path for integer data? D. Explain how the floating-point versions can have CPES of 3.00, even though the multiplication operation requires 5 clock cycles.
B. For data type double, what lower bound on the CPE is determined by the critical path? C. Assuming similar instruction sequences for the integer code as well, what lower bound on the CPE is determined by the critical path for integer data? D. Explain how the floating-point versions can have CPES of 3.00, even though the multiplication operation requires 5 clock cycles.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
![Inner loop of inner4. data_t = double, OP = *
udata in %rbp, vdata in %rax, sum in %xmmo
i in %rcx, limit in %rbx
1
.L15:
loop:
vmovsd 0(%rbp,%rcx,8), %xmm1
vmulsd (%rax,%rcx,8), %xmm1, %xmm1
vaddsd %xmm1, %xmm0, %xmmo
$1, %rcx
%rbx, %rcx
2
Get udata[i]
3
Multiply by vdata[i]
4
Add to sum
addq
Increment i
Compare i:limit
If !=, goto loop
стра
7
jne
.L15
Assume that the functional units have the characteristics listed in Figure 5.12.
A. Diagram how this instruction sequence would be decoded into operations
and show how the data dependencies between them would create a critical
path of operations, in the style of Figures 5.13 and 5.14.
B. For data type double, what lower bound on the CPE is determined by the
critical path?
C. Assuming similar instruction sequences for the integer code as well, what
lower bound on the CPE is determined by the critical path for integer data?
D. Explain how the floating-point versions can have CPES of 3.00, even though
the multiplication operation requires 5 clock cycles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35cabfee-9116-4257-bdac-4e17d3de935c%2F08e96252-af27-412c-bf70-7b6b686c1c55%2Fsr1eoag_processed.png&w=3840&q=75)
Transcribed Image Text:Inner loop of inner4. data_t = double, OP = *
udata in %rbp, vdata in %rax, sum in %xmmo
i in %rcx, limit in %rbx
1
.L15:
loop:
vmovsd 0(%rbp,%rcx,8), %xmm1
vmulsd (%rax,%rcx,8), %xmm1, %xmm1
vaddsd %xmm1, %xmm0, %xmmo
$1, %rcx
%rbx, %rcx
2
Get udata[i]
3
Multiply by vdata[i]
4
Add to sum
addq
Increment i
Compare i:limit
If !=, goto loop
стра
7
jne
.L15
Assume that the functional units have the characteristics listed in Figure 5.12.
A. Diagram how this instruction sequence would be decoded into operations
and show how the data dependencies between them would create a critical
path of operations, in the style of Figures 5.13 and 5.14.
B. For data type double, what lower bound on the CPE is determined by the
critical path?
C. Assuming similar instruction sequences for the integer code as well, what
lower bound on the CPE is determined by the critical path for integer data?
D. Explain how the floating-point versions can have CPES of 3.00, even though
the multiplication operation requires 5 clock cycles.
![Suppose we wish to write a procedure that computes the inner product of two
vectors u and v. An abstract version of the function has a CPE of 14–18 with x86-
64 for different types of integer and floating-point data. By doing the same sort
of transformations we did to transform the abstract program combine1 into the
more efficient combine4, we get the following code:
/* Inner product. Accumulate in temporary */
void inner4(vec_ptr u, vec_ptr v, data_t *dest)
1
{
long i;
long length
data_t *udata = get_vec_start(u);
data_t *vdata = get_vec_start (v);
data_t sum = (data_t) 0;
4
vec_length(u);
%3D
8.
9.
for (i = 0; i < length; i++) {
sum = sum + udata[i] * vdata[i];
10
11
12
}
13
*dest = sum;
14
Our measurements show that this function has CPES of 1.50 for integer data
and 3.00 for floating-point data. For data type double, the x86-64 assembly code
for the inner loop is as follows:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35cabfee-9116-4257-bdac-4e17d3de935c%2F08e96252-af27-412c-bf70-7b6b686c1c55%2Fcc3cnvg_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose we wish to write a procedure that computes the inner product of two
vectors u and v. An abstract version of the function has a CPE of 14–18 with x86-
64 for different types of integer and floating-point data. By doing the same sort
of transformations we did to transform the abstract program combine1 into the
more efficient combine4, we get the following code:
/* Inner product. Accumulate in temporary */
void inner4(vec_ptr u, vec_ptr v, data_t *dest)
1
{
long i;
long length
data_t *udata = get_vec_start(u);
data_t *vdata = get_vec_start (v);
data_t sum = (data_t) 0;
4
vec_length(u);
%3D
8.
9.
for (i = 0; i < length; i++) {
sum = sum + udata[i] * vdata[i];
10
11
12
}
13
*dest = sum;
14
Our measurements show that this function has CPES of 1.50 for integer data
and 3.00 for floating-point data. For data type double, the x86-64 assembly code
for the inner loop is as follows:
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