(b) The simple DC circuit in Figure 2.0 is powered by a 15 volts DC battery input-source (V₁) which will cause currents to flow through the resistors, R₁, R₂ and R3 as illustrated. When current flows through a resistor, it creates a voltage across the resistor as governed by the Ohm's Law expression, V = I.R. The Kirchhoff's Current Law (KCL) states that the sum of all currents entering (or leaving) a node is zero. Therefore, I₁ + (- 1₂) + (-13) = 0, resulting in I₁ = I₂ + 13. Even though the basic circuit laws may not be fully covered in class as yet, you may use the above circuit law expressions to determine the missing values in Table 2.0. Show your analysis on the below workspace provided. Note: 1 mA = 1x10 ³A = 0.001A; and 1 k = 1x10³0 = 10000 V₁ (15 volts) R₁ (10 km) M + R₂ (10 kn) V3 R3 | (10 ΚΩ)
(b) The simple DC circuit in Figure 2.0 is powered by a 15 volts DC battery input-source (V₁) which will cause currents to flow through the resistors, R₁, R₂ and R3 as illustrated. When current flows through a resistor, it creates a voltage across the resistor as governed by the Ohm's Law expression, V = I.R. The Kirchhoff's Current Law (KCL) states that the sum of all currents entering (or leaving) a node is zero. Therefore, I₁ + (- 1₂) + (-13) = 0, resulting in I₁ = I₂ + 13. Even though the basic circuit laws may not be fully covered in class as yet, you may use the above circuit law expressions to determine the missing values in Table 2.0. Show your analysis on the below workspace provided. Note: 1 mA = 1x10 ³A = 0.001A; and 1 k = 1x10³0 = 10000 V₁ (15 volts) R₁ (10 km) M + R₂ (10 kn) V3 R3 | (10 ΚΩ)
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Transcribed Image Text:(b) The simple DC circuit in Figure 2.0 is powered by a 15 volts DC battery input-source (V₁) which will cause
currents to flow through the resistors, R₁, R₂ and R3 as illustrated. When current flows through a resistor, it
creates a voltage across the resistor as governed by the Ohm's Law expression, V = I.R. The Kirchhoff's
Current Law (KCL) states that the sum of all currents entering (or leaving) a node is zero. Therefore, I₁ +
(- 1₂) + (-13) = 0, resulting in I₁ = I₂ + I3.
Even though the basic circuit laws may not be fully covered in class as yet, you may use the above circuit
law expressions to determine the missing values in Table 2.0. Show your analysis on the below workspace
provided. Note: 1 mA = 1x10 ³A = 0.001A; and 1 k = 1x10³Q = 10000
V₁
(15 volts)
4₁→
h
R₁ (10 km)
M
+
V₁
+
R₂V₂
(10 km)
V3 R3
(10 kn)
13
↓ ↓
Figure 2.0: Simple D.C. circuit for voltage and current measurements
Transcribed Image Text:Pre-Lab workspace
V₁
V₂
V3
5 volts
Table 2.0
I₁
I₂
0.5 mA
13
What relationship exists between voltages V₂ and V3? and between currents, I2 and 13? Why?
Was the voltage relationship V₁ = V₁ + (V2 or V3) established? If so, why would it be the case?
If the resistor, R₁ is replaced with a wire (i.e. make R₁ = 0 22), intuitively what might the resultant value of the
voltage, V3 be? Explain.
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