Table 2. Series Circuit Data V1 I1 V2 I2 Vi+V2 (volts) (mA) (volts) (mA) (volts) (mA) (volts) 6V 16.2 mA 6V 16.2 mA. 6V 16.2 mA ? T=V/R = 6/370 = .0162 Ax 1000 mA/A =16.2

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R1 is 150 ohms, and R2 is 220 ohms. (150 +220 = 370). In a series circuit, the current is the same across the circuit.  The available power storage is 6 volts.  The problem I am have is conceptualizing what V1 + V2 equals.  I conjecture that the sum would be less than 6 V.  I can't say 3 + 3 =6 V, but rather V1 + V2 < 6?

Unless R1=R2, then perhaps 3 + 3 = 6V.  However, R1 is 150 ohms, and R2 is 220 ohms.

Complicating issue, if I use an ammeter and voltmeter, these devices may have some internal resistance, so equals becomes < 6 V?

How then do I conceptualize better, V1 + V2, so that maybe it is based on the value of the individual Resistor?

 

Table 2. Series Circuit Data
V1
I1
V2
I2
Vi+V2
(volts)
(mA)
(volts)
(mA)
(volts)
(mA)
(volts)
6V
16.2 mA
6V
16.2 mA.
6V
16.2 mA ?
T=V/R = 6/370 = .0162 Ax 1000 mA/A =16.2
Transcribed Image Text:Table 2. Series Circuit Data V1 I1 V2 I2 Vi+V2 (volts) (mA) (volts) (mA) (volts) (mA) (volts) 6V 16.2 mA 6V 16.2 mA. 6V 16.2 mA ? T=V/R = 6/370 = .0162 Ax 1000 mA/A =16.2
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