5. An electric circuit contains a resistance R and a capacitor C in series, and a battery supplying a time-varying electromotive force (or voltage) V(t). The charge q on the capacitor therefore obeys the following differential equation: Rda + 2 = V(t). Assuming that initially there is no charge on the capacitor, and given that V(t) Vosinut, where V, and w are some constants, find the charge on the capacitor as a function of time. =

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5. An electric circuit contains a resistance R and a capacitor C in series, and a battery
supplying a time-varying electromotive force (or voltage) V(t). The charge q on the
capacitor therefore obeys the following differential equation:
Rdq + 2 = V(t).
dt
Assuming that initially there is no charge on the capacitor, and given that V(t)
Vosinut, where V₂ and w are some constants, find the charge on the capacitor as a
function of time.
=
Hint: You may have to do integration by parts twice to evaluate the following inte-
gral: feRc sin(wt)dt.
Transcribed Image Text:5. An electric circuit contains a resistance R and a capacitor C in series, and a battery supplying a time-varying electromotive force (or voltage) V(t). The charge q on the capacitor therefore obeys the following differential equation: Rdq + 2 = V(t). dt Assuming that initially there is no charge on the capacitor, and given that V(t) Vosinut, where V₂ and w are some constants, find the charge on the capacitor as a function of time. = Hint: You may have to do integration by parts twice to evaluate the following inte- gral: feRc sin(wt)dt.
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