(b) The memory unit of a computer has 256K words of 32 bits each. The computer has an instruction format with four fields: an operation code field, a mode field to specify one of seven addressing modes, a register address field to specify one of 60 processor registers, and a memory address. Specify the instruction format and the number of bits in each field of the instruction if instruction is in one memory word.
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Q: Example 2: Define machine cycle, describe the contents of the address, data and control bus lines…
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A: The answer will be:- 6234H
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Q: 3-Assume a program requires the execution of 50 × 106 FP instructions, 110 × 106 INT instructions,…
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Q: 3-Assume a program requires the execution of 50 × 106 FP instructions, 110 x 106 INT instructions,…
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Q: 3-Assume a program requires the execution of 50 x 106 FP instructions, 110 x 106 INT instructions,…
A: The answer is..
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A: Answer: a) b) c) i) ii)
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A: The answer given as below:
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Q: If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] + 1234H,…
A: Answer: It is a base addressing mode. Effective address of the operand obtained by adding direct or…
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?A(n) __________ is a storage location implemented in the CPU.The memory unit of a computer has 2M words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 4 addressing modes; a register address field to specify one of 9 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: c) How large must the address field be?
- The memory unit of a computer has 2M words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 4 addressing modes; a register address field to specify one of 9 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: b) How large must the register field be?The memory unit of a computer has 2M words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 4 addressing modes; a register address field to specify one of 9 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following: a) How large must the mode field be?The memory unit of a computer has 256K words of 32 bits each. The computer has an instruction format with 4 fields: an opcode field; a mode field to specify 1 of 7 addressing modes; a register address field to specify one of 60 registers; and a memory address field. Assume an instruction is 32 bits long. Answer the following:a. How large must the mode field be?b. How large must the register field be?c. How large must the address field be?d. How large is the opcode field?
- The code segment, the data segment, and the stack segment are all distinct. Then, determine the mix of registers utilized to address data objects in each segment.Computer Science A computer uses a memory of 64K words with 16 bits in each word.It has the following registers: PC, AR, TR, AC, DR and IRA memory-reference instruction consists of two words: an 16-bit operation-code(one word) and an address field (in the next word).a-List the sequence of microoperations for fetching a memory reference instructionand then placing the operand in DR. Start from timing signal To.b-Design the logic control gates arrangement to perform the fetch instructions.Given the content of memory and the registers below. i. ii. iii. Indicate the type of addressing mode of each line of instruction below Deduce the target addressDeduce the Value loaded into accumulator register (A) Data at location Memory Address 03600 3030 103000 3600 00C303 6390 003030 C303 Memory content Base Register (B) 00600 Program Counter (Pc) 003000 Index Register (X) 000090 Register ContentInstructionsOpcodes - LDA = 00 SN opcode n i x b p e Displacement Target Address (TA) 1 000000 1 1 0 0 1 0 0110 0000 0000 2 000000 1 1 1 1 0 0 0011 0000 0000 3 000000 1 0 0 0 1 0 0000 0011 0000 4 000000 0 1 0 0 0 0 0000 0011 0000 5 000000 1 1 0 0 0 1 0000 1100 0011 0000 0011
- QuedT: Choose the correct answer: [ Opcode, funct3 and funct7/6 in instruction format are used to identify the: (a) function. (b) instruction. (e) branch. (d) memory address. The register that hold the address of the current instruction being executed is called: (a) saved register. (b) global pointer. (e) stack pointer. (d) program counter. Placing the executable file into the memory for execution by the processor is the role of (a) assembler. (b) linker. (e) loader. (d) compiler. The part which responsible for transmitting the data to/from the processor is: (a) control unit. (b) Datapath. (c) data bus. (d) memory. Parallel hardware cannot be used for faster division because: (a) subtraction is conditional on sign of remainder. (b) multiplication is conditional on sign of remainder. (c) subtraction is conditional on sign of divisor. (d) multiplication is conditional on sign of divisor. we cannot slower the clock cycle to fit the floating-point adder algorithm into one clock cycle…Assume that the instruction pointer, EIP, contains 10410 and the assembly language representation of the instruction in memory at address 10410 is JNE 59. If the flags are currently CF=1, ZF=0 and SF=1 what is the value of the EIP after the instruction executes?An instruction is stored at location100 with its address field at location 110. The address field has the value 300. The value at location 200 is 300, at 300 is 400, and at 400 is 500. Draw a memory diagram to describe this data. Evaluate the effective address and the operand, if the addressing mode of the instruction is (i) Direct (ii) Indirect, and (iii) Immediate. explain in detail.