B R,=12002 V=7V 1,= 5.9m A R = 5602 V =6.06V I =10.6mA I= 16.4mA E = 11.7V Red + D E Green - R; = 2202 Vs = 0.av Is = 11.7mA %3D R, = 4732 R = 8202 %3D V,=4.65V V. = 5.56v I, = 5.56mA 1, = 4.9 mA F G H
B R,=12002 V=7V 1,= 5.9m A R = 5602 V =6.06V I =10.6mA I= 16.4mA E = 11.7V Red + D E Green - R; = 2202 Vs = 0.av Is = 11.7mA %3D R, = 4732 R = 8202 %3D V,=4.65V V. = 5.56v I, = 5.56mA 1, = 4.9 mA F G H
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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For this question use the data given in the circuit to verify kirchoffs junction rule. Please show all steps and use kirchoffs junction rule.
![A
B
C
R,=12002
V;=7V
1,= 5.9m A
R = 5602
V =6.06V
I =10.6mA
%3D
I= 16.4mA
E = 11.7V
Red +
D
E
Green -
R5 = 2202
V =
Is = 11.7mA
= 0. aV
%3D
R, = 4732
V, =4,65V
= 8202
RA
V = 5.56v
I = 5.56mA
1, = 4.9 mA
F
G
H](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19dbe7d3-bfca-4b5b-933b-abb925e760a3%2F9976e11c-201c-4753-9244-b4d4eb7f6405%2Fnx4ad4a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A
B
C
R,=12002
V;=7V
1,= 5.9m A
R = 5602
V =6.06V
I =10.6mA
%3D
I= 16.4mA
E = 11.7V
Red +
D
E
Green -
R5 = 2202
V =
Is = 11.7mA
= 0. aV
%3D
R, = 4732
V, =4,65V
= 8202
RA
V = 5.56v
I = 5.56mA
1, = 4.9 mA
F
G
H
![Junction B:
The currents entering junction B
The currents leaving junction B
Test the junction rule:
Junction D: Repeat the above calculation for Junction D.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19dbe7d3-bfca-4b5b-933b-abb925e760a3%2F9976e11c-201c-4753-9244-b4d4eb7f6405%2F5vq8tql_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Junction B:
The currents entering junction B
The currents leaving junction B
Test the junction rule:
Junction D: Repeat the above calculation for Junction D.
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