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1 ohm 1 ohm 10 sin (3t)() L= 2/3 h C = 1/6 F Solve for the current provided by the voltage source in the circuit diagram above. (HINT: / strongly recommend reviewing Lecture 9. This is not a hard problem to calculate, but understanding a rigorous method to do so might be a little trickier.) u

1 ohm 1 ohm 10 sin (3t)() L= 2/3 h C = 1/6 F Solve for the current provided by the voltage source in the circuit diagram above. (HINT: / strongly recommend reviewing Lecture 9. This is not a hard problem to calculate, but understanding a rigorous method to do so might be a little trickier.) u

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1 ohm 1 ohm 10 sin (3t)() EL= 2/3 h C = 1/6 F Solve for the current provided by the voltage source in the circuit diagram above. (HINT: / strongly recommend reviewing Lecture 9. This is not a hard problem to calculate, but understanding a rigorous method to do so might be a little trickier.) 1 ohm 1 ohm 10 sin (3t)() C= 1/3 f %=D1/3h Solve for the current provided by the voltage source in the circuit diagram above. (HINT: / strongly recommend reviewing Lecture 9. This is not a hard problem to calculate, but understanding a rigorous method to do so might be a little trickier.)
Transcribed Image Text:1 ohm 1 ohm 10 sin (3t)() EL= 2/3 h C = 1/6 F Solve for the current provided by the voltage source in the circuit diagram above. (HINT: / strongly recommend reviewing Lecture 9. This is not a hard problem to calculate, but understanding a rigorous method to do so might be a little trickier.) 1 ohm 1 ohm 10 sin (3t)() C= 1/3 f %=D1/3h Solve for the current provided by the voltage source in the circuit diagram above. (HINT: / strongly recommend reviewing Lecture 9. This is not a hard problem to calculate, but understanding a rigorous method to do so might be a little trickier.)
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