College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
Apply the Loop Rule to ABCKFA.

Transcribed Image Text:This image depicts an electrical circuit, commonly known as a Wheatstone bridge, which is used for measuring unknown electrical resistances. The circuit diagram includes five resistors and a galvanometer. Below is a detailed description of the components and their configuration.
### Components:
- **Resistors:**
- \( R_{AB} \): Resistor between points A and B.
- \( R_{BC} \): Resistor between points B and C.
- \( R_{CD} \): Resistor between points C and D.
- \( R_{AD} \): Resistor between points A and D.
- \( R_{G} \): Resistor connected across the galvanometer (between points B and D).
- **Galvanometer (G):**
- Located on the line connecting points B and D and denoted by the letter G. It measures the current flow through this section.
- **Battery:**
- Provides a voltage \( V_o \) and is connected at points F and K, creating a complete circuit.
### Circuit Pathways and Currents:
- Current \( I_1 \) flows from point A to point B.
- Current \( I_2 \) flows from point A to point D.
- Current \( I_3 \) flows through the galvanometer from point B to point D, intersecting at point H.
### Functionality:
In this Wheatstone bridge configuration, the balance condition is achieved when the ratio of the resistances \( \frac{R_{AB}}{R_{BC}} = \frac{R_{AD}}{R_{CD}} \). Under this balance condition, the current through the galvanometer \( G \) becomes zero, indicating that the bridge is balanced, allowing for the calculation of an unknown resistance if three of the resistor values are known.
This circuit is a fundamental tool in electrical engineering and physics for precision measurement of electrical resistances.

Transcribed Image Text:Use Kirchhoff’s junction rule and voltage/loop rule to find the current through each resistor in the following circuit: \( R_{AB} = 10 \, \Omega, \, R_{BC} = 15 \, \Omega, \, R_{AD} = 6 \, \Omega, \, R_{CD} = 12 \, \Omega, \, R_{G} = 4 \, \Omega, \) and \( V_o = 10 \, \text{V}. \)
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