(b) Let x(t) be a real-valued signal with X (w) = 0 when |w| > 990n. Amplitude modulation is performed to produce the signal g(t) = x(t) cos(1000nt). A proposed demodulation technique shown in Figure Q3 (b) consists of multiplying the modulated signal by sin(1000nt) and passing through a lowpass filter with the cutoff frequency 1000r. Determine y(t). ideal low-pass filter with cut-off g(1) = x(t)cos (1000 t)→(x y(t) frequency 1000r sin (1000 r t) Figure Q3 (b)

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(b) Let x(t) be a real-valued signal with X (w) = 0 when |w| > 990n. Amplitude
modulation is performed to produce the signal g(t) = x(t) cos(1000nt).
A proposed demodulation technique shown in Figure Q3 (b) consists of
multiplying the modulated signal by sin(1000nt) and passing through a
lowpass filter with the cutoff frequency 1000. Determine y(t).
ideal low-pass
filter with cut-off
frequency 1000r
g(?)= x(t )cos(1000 z t)→(x
y(t)
sin (1000 x t)
Figure Q3 (b)
Transcribed Image Text:(b) Let x(t) be a real-valued signal with X (w) = 0 when |w| > 990n. Amplitude modulation is performed to produce the signal g(t) = x(t) cos(1000nt). A proposed demodulation technique shown in Figure Q3 (b) consists of multiplying the modulated signal by sin(1000nt) and passing through a lowpass filter with the cutoff frequency 1000. Determine y(t). ideal low-pass filter with cut-off frequency 1000r g(?)= x(t )cos(1000 z t)→(x y(t) sin (1000 x t) Figure Q3 (b)
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