(b) In two dimensional boundary layer, shear stress was changed linearl; the solid surface toward y-axis until it reach the value of zero at Based on Table 2 and setting given to you; (i) Derive the equation of displacement thickness and mom thickness using Von Karman Approximation Method ; and (ii) Determine the accuracy of this method in determining the va displacement thickness and momentum thickness. Table 2 : Equation of Velocity Profile Setting Equation
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- (b) In two dimensional boundary layer, shear stress was changed linearly from the solid surface toward y-axis until it reach the value of zero at y = ở. Based on Table 2 and setting given to you; (i) Derive the equation of displacement thickness and momentum thickness using Von Karman Approximation Method ; and (ii) Determine the accuracy of this method in determining the value of displacement thickness and momentum thickness. C5 Table 2: Equation of Velocity Profile Setting Equation wU = 2y/8 - (y/S² 1(b) In two-dimensional boundary layer, shear stress was changed linearly from the solid surface toward y-axis until it reach the value of zero at y = 8. Based on Table 2 and setting given to you; (i) Derive the equation of displacement thickness and momentum thickness using Von Karman Approximation Method ; and (ii) Determine the accuracy of this method in determining the value of displacement thickness and momentum thickness. Table 2: Equation of Velocity Profile Equation u/U = 3(y/S)/2 – (y/8)³/2(b) In two-dimensional boundary layer, shear stress was changed linearly from the solid surface toward y-axis until it reaches the value of zero at y = 8. Based on Table 2 and setting given to you; (i) Derive the equation of displacement thickness and momentum thickness using Von Karman Approximation Method; and (ii) Determine the accuracy of this method in determining the value of displacement thickness and momentum thickness. Table 2: Equation of Velocity Profile Equation u/U = 3(y/8)/2 – (y/8)³/2 Setting 2
- Find the equation of motion (Navier Stokes) for a viscous fluid between two rotating concentric cylinders (axle and shaft). The inner cylinder has the radius ro and rotates at angular speed wo. The outer cylinder has the radius R and is stationary. Write down each vector component of the equation in a separate line and use reasonable assumptions to simplify the equation, especially the derivatives. Be sure to use cylindrical coordinates for the convective operator and the other derivatives.Consider the 2-D incompressible, invisicid Navier-Stokes equation in the horizontal plane. Recall that the momentum equations are simply solving the transport of the velocity on a frozen velocity field. Use a finite volume method on a structured grid numbered i, j with uniform h = 0.3 in x and y, as shown in Fig. 4. Use typical numbering, e.g. ui,j refers to the solution for the i-th point in the x-, and j-th point in the y-direction. The fluid has a density of 1000 kgm3. Use first-order upwinding for the fluxes.The pressure field of the initial solution is taken as uniform pi,j = 0.Assume that you have computed the first step of the SIMPLE scheme from an initial solution, and the resulting velocity field u* is given by the components u = [u, v] ^T with u1,j = 1.1, u2,j= 1.5, u3,j = 2.5for all j except cell 2, 2, and ui,1 = 0.3, ui,2 = 0.5, ui,3 = 0.8 for all i except cell 2, 2. In cell 2,2 the velocity is u2,2 = [2, 0.6]^T. a) Simplify the equations for the x− and y-momentum for this…PLEASE BOX YOUR ANSWERS Problem 2 In an experiment conducted in a laboratory, the surface tension (Y) acting on a rotating square plate in a viscous fluid is a function of the external torque (t), plate length (a), area moment of inertia of plate (I), specific weight of the fluid (Y) and angular displacement of the plate (0). Using Buckingham-Pi theorem, find a suitable set of pi terms (in M, L and T primary dimensions). Your final answer should be written in proper functional form. Refer Table 5.1/ page-296 for secondary dimension of the variables.
- This exercise is part of a series of problems aimed at modeling a situation by progressively refining our model to take into account more and more parameters. This progressive approach is very close to whatwhat do professional scientists do! contextWe want to lower a suspended load in a controlled way, so that it hits the ground with a speed whose modulus is not too great. To slow down the descent, we added a resort behind the mass (A), Lasuspended load (B) is connected by a rope passing through a pulley to another mass (A), which slides on a horizontal surface with friction.InformationThe masses of loads A and B are known.The mass of the rope itself is negligible (very small compared to the loads).The pulley has negligible mass and can rotate without friction.Load B is initially stationary and is at a known height h.The surface on which mass A is placed is horizontal.There is friction under mass A: the kinetic friction coefficient u, is known.The rope attached to mass A is perfectly…Consider the following equation: 1 dollar bill ≈ 6 in. Is thisrelation dimensionally inconsistent? Does it satisfy thePDH? Why?Consider the 2-D incompressible, invisicid Navier-Stokes equation in the horizontal plane. Recall that the momentum equations are simply solving the transport of the velocity on a frozen velocity field. Use a finite volume method on a structured grid numbered i, j with uniform h 0.3 in x and y, as shown in Fig. 4. Use typical numbering, e.g. ui, refers to the solution for the i-th point in the x-, and j-th point in the y-direction. = i- 1,j+1 i,j+1 i-1,j i-1,j-1 X i,j i+1, j+1 i+1,j i,j-1 i+1,j-1 Figure 4: Two-dimensional grid with equal spacing. The fluid has a density of 1000 kg. Use first-order upwinding for the fluxes. The pressure field of the initial solution is taken as uniform pij = 0. Assume that you have computed the first step of the SIMPLE scheme from an initial solution, and the resulting velocity field u* is given by the components u = [u, v]T with u₁.j = 1.1, U2,j 1.5, U3,j = 2.5 for all j cell 2, 2, and u₁,1 = 0.3, ui,2 = 0.5, U₁,3 = 0.8 for all i except cell 2, 2. In…
- An incompressible Newtonian liquid is confined between two concentric circular cylinders of infinite length— a solid inner cylinder of radius Ri and a hollow, stationary outer cylinder of radius Ro. The inner cylinder be stationary and the outer cylinder rotate at angular velocity ?o. Generate an exact solution for u?(r) using the step-by-step . The flow is steady, laminar, and two-dimensional in the r?-plane. The flow is also rotationally symmetric, meaning that nothing is a function of coordinate ? (u? and P are functions of radius r only). The flow is also circular, meaning that velocity component ur = 0 everywhere. Generate an exact expression for velocity component u? as a function of radius r and the other parameters in the problem. You may ignore gravity.In the study of turbulent flow, turbulent viscous dissipation rate ? (rate of energy loss per unit mass) is known to be a function of length scale l and velocity scale u′ of the large-scale turbulent eddies. Using dimensional analysis (Buckingham pi and the method of repeating variables) and showing all of your work, generate an expression for ? as a function of l and u′.An underwater device which is 2m long is to be moved at 4 m/sec. If a geometrically similar model 40 cm long is tested in a variable pressure wind tunnel at a speed of 60 m/sec with the following information, Poir at Standard atmospheric pressure = 1.18kg/m³ Pwater = 998kg/m3 Hair = 1.80 x 10-5 Pa-s at local atmospheric pressure and Hwater = 1 × 10-3 Pa-s then the pressure of the air in the model used times local atmospheric pressure is