(b) A plastic rod AB of length L =510 mm has a diameter d, = 30 mm as shown in Figure Q2(b). A plastic sleeve CD of length c = 300 mm and outer diameter d = 45 mm is securely bonded to the rod so that no slippage can occur between the rod and the sleeve. The rod is made of an acrylic with modulus of elasticity E1 = 3.1GPa and the sleeve is %3D made of a polyamide with E2 = 2.5GPa. (i) Calculate the elongation & of the rod when it is pulled by axial forces P=15KN. (ii) If the sleeve is extended for the full length of the rod, what is the elongation? (iii) If the sleeve is removed, what is the elongation?

(b) A plastic rod AB of length L =510 mm has a diameter d, = 30 mm as shown in Figure Q2(b). A plastic sleeve CD of length c = 300 mm and outer diameter d = 45 mm is securely bonded to the rod so that no slippage can occur between the rod and the sleeve. The rod is made of an acrylic with modulus of elasticity E1 = 3.1GPa and the sleeve is %3D made of a polyamide with E2 = 2.5GPa. (i) Calculate the elongation & of the rod when it is pulled by axial forces P=15KN. (ii) If the sleeve is extended for the full length of the rod, what is the elongation? (iii) If the sleeve is removed, what is the elongation?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: The pin-connectsed structure consists of a rigid bar ABCD and two bronze alloy [E = 100 GPa] bares,…

A: GivenE=100GPaA=340mm2L1=810mmL2=1080mma=480mmb=38mmc=600mmσlim=165MPa

Q: The truss in the figure below is under the effect of one load, this truss consists of three parts,…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: You are holding a thin and weightless bar on your head (see figure 2.1). On the extremity A, the bar…

A: Given:k=50 N/mAE=1.58496 m

Q: Consider the thermal effects on materials The rails of a railroad track are welded together at their…

A: The stress developed due to temperature change is called thermal stress. For free expansion thermal…

Q: Question (4): A plastic bar ACB having two different solid circular cross sections is held between…

Q: Consider the bar in figure 2, it has cross sectional area A = 1.10-4m², modulus of elasticity E =…

A: The displacement of bar is The cross sectional area is The modulus of elaticity is

Q: Q2\ Find the necessary change in temperature in the copper bar so that the rigid bar remains…

A: For the rigid bar to remain horizontal, the moment due to the UDL should be equal to the moment due…

Q: What is the minimum required diameter of the rod if the factor of safety for tension failure is F.S.…

A: Given,load, P = 11 kN = 11,000 NFailure stress, σ= 60 Mpa = 60 N/mm2Factor of safety, FS =…

Q: A copper bar with rectangular cross-section is hung from a rigid pin that is supported by two steel…

Q: 1-A solid axial member which is made from three parts with different materials (sections 1 and 3) is…

A: I have used the first row for the values of youngs modulus. NOTE: According to Bartleyby's policy we…

Q: A steel cable with nominal diameter 25 mm as shown in Table Q2(a) is used in a construction yard to…

Q: A rectangular polypropylene [E = 6,200 MPa] bar (1) is connected to a rectangular nylon [E = 1,400…

Q: Rigid bar ABCD is loaded and supported as shown. Bars (1) and (2) are unstressed before the load P…

Q: SEE IMAGES AND FIND ANSWERS... PLEASE

A: Given data as per the question Considering the given diagram and drawing the free body diagram

Q: a) The total strain energy for a bar of length L. is given by the equation -J. 2EA. How would the…

A: we have to determine the effect of making the bar tapered.

Q: A steel rod with a radius of 2.5 cm, the ends of which are fixed, is subjected to a tension force of…

Q: Rigid bar ABCD is loaded and supported as shown. Steel [E = 28600 ksi] bars (1) and (2) are…

A: Given data: A1=0.67 in2A2=0.32 in2ε1=810 μ Need to determine the stresses in bars 1 and 2, vertical…

Q: MECHANICS OF DEFORMABLE BODIES WITH ME APPLICATION - STRAIN Problem 2.13 rigid bar with negligible…

Q: Q2: Consider a bar shown in figure Q2 with an axial load P = 75 kN applied as shown. The bar is…

Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

(b) A plastic rod AB of length L = 510 mm has a diameter d, = 30 mm as shown in Figure
Q2(b). A plastic sleeve CD of length c = 300 mm and outer diameter d2 = 45 mm is
securely bonded to the rod so that no slippage can occur between the rod and the sleeve.
The rod is made of an acrylic with modulus of elasticity E1 = 3.1GPA and the sleeve is
made of a polyamide with E2 = 2.5GP .
(i)
Calculate the elongation & of the rod when it is pulled by axial forces P=15KN .
(ii)
If the sleeve is extended for the full length of the rod, what is the elongation?
(iii) If the sleeve is removed, what is the elongation?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

A polyethylene bar with a diameter d,= 4.0 in. is placed inside steel lube with an inner diameter d2=4.01 in.(see figure). the polythylene bar is then conpressed by an axial force p. At what value of the bforce P will the space between the poltyethylene bar and the steel tube be closed ? for polythelene,assume E=200 ksi and v=0.4.
Help me with this plaese
Problem 2. A block of cast iron was wrapped in the thin aluminum foil as shown on the figure. At room temperature there is no stress on the foil. The whole system is then immersed in liquid nitrogen at -196°C. Find the stress on the aluminum foil. Is the foil going to deform permanently? Is it going to break? Stress [MPa] 350 300 250 200 150 100 50 0 0 alu alloy 5083-H34 0.005 0.01 0.015 0.02 Strain Aluminum foil 5 µm thick, this is a continuous strip with the ends welded together Cast iron 20 mm thick a aluminum = 2.4 105 K-¹, Stress MPa 400 300 200 100 a iron 1.2 105 K-1 ↑ 11 0 0 0.05 0.1 0.15 0.2 0.25 Strain Fig. 2. Stress-strain diagrams for aluminum. Left: Low strain region. Right: Full strain range. Hint: you can get the Young's modulus, proportions limit (elastic limit), and break point from the graphs.
A steel rod with a cross-sectional area of 150mm^2 is stretched between two fixed points. The tensile load at 20°C is 5000N. (a) What will be the stress at -20°C? (b) At what temperature will the stress be zero? Assume (E=200x10^9N/m^2, α=11.7 um/cm°C)
Q2: The pin-connected structure shown in Figure consists of a rigid bar ABCD and two axial members. Bar (1) is steel /E = 200 GPal with a cross-sectional area of (4,= 400 mm). Bar (2) is an aluminum alloy (E = 70 GPaj with a cross-sectional area of (A, = 400 mmj. The bars are unstressed when the structure is assembled. After a concentrated load of [P- 36 kNJ is applied, determine: (a) the normal stresses in bars (1) and (2). (b) the deflection of point D on the rigid bar. 900 mm Area=40omnt (1) 350 mm alumiaum (2) 36 AN 600 mm Ag= Yoom 720 mm
A steel rod 10 mm in diameter and Im long is heated from 20°C to 120°C, E = 200 GPa and a = 12 × 106 per °C. If the rod is not free to expand, the thermal stress developed is: (a) 120 MPa (tensile) (c) 120 MPa (compressive) (b) 240 MPa (tensile) (d) 240 MPa (compressive)
A 200-kg load is hung on a wire having a length of 4.00 m, cross-sectional area 0.200 x10-4m², and Young's modulus 8.00 x 1010N/m². What is its increase in length?
An aluminum alloy [E = 70 GPa; v = 0.33; a = 23.0x10-6/°C] pipe is subjected to a tensile load P. The pipe has an outside diameter of D = 280 mm, a cross-sectional area of A = 7550 mm², and a length of L = 9.5 m. The initial longitudinal normal strain in the pipe is zero. After load P is applied and the temperature of the pipe has been increased by AT = 40°C, the longitudinal normal strain in the pipe is found to be 2260 με. Calculate the magnitude of load P. Answer: P = M. L kN D P
Consider the bar in Figure 2, which has cross-sectional area A = 1·10−3 m2, modulus of elasticityE = 1·1011 N/m2, and length 1 m. The bar is fixed to a wall on its left hand side. Along the left halfof the bar, x=[0 m, 0.5 m], there is a constant distributed force of l(x) = 10 kN/m. Along the righthalf of the bar, x=[0.5 m, 1 m], there is a constant distributed force of l(x) = 20 kN/m. a) Given the finite element mesh in Figure 3, consisting of two elements of equal size L = 0.5 m,sketch the associated basis functions of the mesh, and write the approximation of the displacementfunction u(x) as an expansion of these basis functions. Use u1, u2 and u3 to denote the expansioncoefficients for each node. b) The general form of the element stiffness matrix system, with nodes indexed by i and j, is givenas shown in the image of eqaution 2, where F0 and f(1) denote boundary forces at positions x = 0 and x = 1, respectively. Form the two basis functions for element 2, and evaluate the right…
An aluminum alloy [E = 70 GPa; v = 0.33; a = 23.0x10-6/°C] bar is subjected to a tensile load P. The bar has a depth of d = 270 mm, a cross-sectional area of A = 13520 mm², and a length of L = 4.5 m. The initial longitudinal normal strain in the bar is zero. After load P is applied and the temperature of the bar has been increased by AT = 46°C, the longitudinal normal strain is found to be 1830 με. Calculate the change in bar depth d after the load P has been applied and the temperature has been increased. P Answer: Δd = i d eTextbook and Media Save for Later L mm Attempts: 0 of 5 used Submit Answer
1 A 12.5 mm diameter steel rod is pinned between two rigid walls. The rod is initially unstressed. The rod's temperature subsequently increases 50°C. The rod is adequately stiffened and supported such that buckling does not occur. The coefficient of linear ther- mal expansion for steel is 11.7 × 10-6 1/°C. The mod- ulus of elasticity for steel is 210 GPa. What is the approximate axial force in the rod? 3.5 m d = 12.5 mm
I need help with part e, thanks