AWWTP effluent of 0.011 m^3 /s and a BOD5 of 590 mg/L discharges into a river. The river has flow of 1.7 m^3 Is., the BOD5 of the river is 0.6 mg/L. The BOD rate constants (k1) are 0.115 day^-1 for the waste water and 3.7 day^-1 for the river. Calculate the initial ultimate BOD (Lo) after mixing. = 9.270 mg/I z 6.452 mg/I - 8.233 mg/l z 7.345 mg/I

AWWTP effluent of 0.011 m^3 /s and a BOD5 of 590 mg/L discharges into a river. The river has flow of 1.7 m^3 Is., the BOD5 of the river is 0.6 mg/L. The BOD rate constants (k1) are 0.115 day^-1 for the waste water and 3.7 day^-1 for the river. Calculate the initial ultimate BOD (Lo) after mixing. = 9.270 mg/I z 6.452 mg/I - 8.233 mg/l z 7.345 mg/I

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

AWWTP effluent of 0.011 m^3 /s and
a BOD5 of 590O mg/L discharges into
a river. The river has flow of 1.7 m^3
Is., the BOD5 of the river is 0.6 mg/L.
The BOD rate constants (k1) are 0.115
day^-1 for the waste water and 3.7
day^-1 for the river. Calculate the
initial ultimate BOD (Lo) after mixing.
z 9.270 mg/I
z 6.452 mg/I
- 8.233 mg/l
z 7.345 mg/I

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