A river with a flowrate (Q) of 850 cfs (cubic feet per second) has a total dissolved solids (TDS, think table salt in water) concentration of 55 mg/L. An industry discharges a water stream with a TDS concentration of 2,500 mg/L into the river and the two streams are well mixed. If the maximum TDS concentration allowed in the river is 250 mg/L, the system is at steady state, and there are no other TDS inputs, answer the following: a) What is the maximum allowable wastewater flow from the industry (in cfs)? b) If the 250 mg/L TDS level is met downstream, what percent of the TDS comes from the industry?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A river with a flowrate (Q) of 850 cfs (cubic feet per second) has a total dissolved solids (TDS, think table salt in water) concentration of 55 mg/L. An industry discharges a water stream with a TDS concentration of 2,500 mg/L into the river and the two streams are well mixed. If the maximum TDS concentration allowed in the river is 250 mg/L, the system is at steady state, and there are no other TDS inputs, answer the following:

a) What is the maximum allowable wastewater flow from the industry (in cfs)?

b) If the 250 mg/L TDS level is met downstream, what percent of the TDS comes from the industry?

Expert Solution
Step 1

Given,

Flow rate of river, Q = 850 cfc= 850 ft3/sec

TDS of river, say C =55 mg/L

 

TDS of discharge from the industry, say Ci = 2500 mg/L

 

a) Let the flow rate of the industrial discharge be Qi (cfs).

 

The resultant TDS for the mixture of the river and the industrial discharge, say Cr can be given as:

Cr=Q×C+Qi×CiQ+Qi  (1)

 

Also, according to the given problem, the maximum allowable TDS = 250 mg/L.

Cr250

Q×C+Qi×CiQ+Qi250

850×55+Qi×2500850+Qi250

850×55+Qi×2500250×850+250Qi

Qi2213=73.667 (cfs)

 

Therefore, the maximum allowable wastewater flow from the industry = 73.667 cfs.

 

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